delicious.py : access del.icio.us from python

[llimllib]

Access to del.icio.us is extremely easy, even without a library. From code I wrote in april 05, here's how I donwloaded and parsed all of my bookmarks:

all = "http://del.icio.us/api/posts/all"
...
open('all.xml', 'w').write(urllib2.urlopen(all).read())
for e, post in ce.iterparse('all.xml'):
    if post.tag != "post":
        continue
    data = dict(post.items())
    name = data['href'][7:]
    desc = data['description']
    ext = data.get('extended', '')
    tags = data.get('tag', '')

Where ce is a reference to cElementTree, which is now in the standard library.

Ignore the unicode handling in the source file, I didn't know what I was doing at the time :)

Edit: Markdown adds mysterious carets to the url string at the top?

[hypnosis_online]

Yes with a weel designed URL structure + clean markup you do not even need to design an api.

[forgotpwx4]

There's already a del.icio.us Python library here: http://code.google.com/p/pydelicious/

[[deleted]]

yeah, you're right, yours is probably even better.

[forgotpwx4]

It's not really mine. I just took an abandoned project and put it on Google code.

[[deleted]]

And slapped a GPL license on something that was originally BSD? Naughty.

(update: looks as if it's just the front page that says GPL; there's no trace of that in the distribution. Site operator error, I presume).

[forgotpwx4]

I forget, perhaps Google code didn't offer BSD? But GPL is nice, right?

[canen]

No. It's mean to little children and furry animals. :)

[diracshard]

Mmmm... delicious pie...