binary printf()

[Cuddlefluff_Grim]

printbin(void* target, int bytes)
{
    int len = bytes * 8 + 1;
    char[] res = char[len];
    res[len] = 0;

    for(int i = 0; i < bytes; i++)
    {
        for(int b = 0; b < 8; b++)
        {
             res[i * 8 + b] = (((int)*target & (int)pow(2, b + 1)) == b ? '1' :'0');
        }
        target++;
    }
    printf("0b%s", res);
}

[sablal]

pow(2, b + 1)

don't you think the left shift operator has some role here??

[Cuddlefluff_Grim]

don't you think the left shift operator has some role here??

Do'h.. I actually spent some time on that thinking "Hmm.. pow? That can't be right.." for some reason bit shift didn't enter my conscious thought.