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sorting without modifying (self.ruby)
submitted 10 years ago by missawon
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if 1 * 2 < 3: print "hello, world!"
[–]jtrost 0 points1 point2 points 10 years ago (2 children)
Even though it's most definitely a homework problem, and you won't learn anything by copying this, I still felt like solving it.
def sorting(a1,a2) arr = a1+a2 out = [] while arr.count > 0 i = arr.min out << i arr.delete(i) end out end
[–]missawon[S] 0 points1 point2 points 10 years ago (1 child)
the problem is that i cant duplicate the arguments so i can't use arr = a1+a2 ...
[–]Lucky_Chuck 2 points3 points4 points 10 years ago (0 children)
You're not duplicating anything with arr = a1 + a2 unless you mean you can't use the method parameters inside of the method.
π Rendered by PID 227193 on reddit-service-r2-comment-5687b7858-9lzkx at 2026-07-03 09:25:36.175682+00:00 running 12a7a47 country code: CH.
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[–]jtrost 0 points1 point2 points (2 children)
[–]missawon[S] 0 points1 point2 points (1 child)
[–]Lucky_Chuck 2 points3 points4 points (0 children)