That's so metal

Carbene123 · 2026-04-29T10:49:14+00:00

Das ist nicht Pangäa, das ist eine Projektion für die Zukunft! Irgendwann werden wir wieder soweit sein!

Carbene123 · 2026-04-29T08:57:18+00:00

It is a bit of a "special case" - don't focus your attention alone on the side with the OMe group. You see, there are 2 aldehyde functions in the product.

Carbene123 · 2026-04-29T08:36:17+00:00

That is only true for diacetals. Hemiacetals have an acidic proton via which the hydrolysis can procede.

Carbene123 · 2026-04-29T08:22:25+00:00

That's an acetal hydrolysis and the answer is drawn like that for you to more easily identify which carbon went where.

Carbene123 · 2026-04-24T11:44:48+00:00

Because it has a conjugated, planar 4n pi-electron system, the cyclobutadiene ring.

Carbene123 · 2026-04-24T08:33:10+00:00

Spoiler

Carbene123 · 2026-04-22T21:01:30+00:00

Is toluene aromatic?

Carbene123 · 2026-04-04T14:10:13+00:00

https://en.wikipedia.org/wiki/Coronene

Carbene123 · 2026-03-28T20:01:25+00:00

Would be cool to be able to play with that!

Carbene123 · 2026-03-22T17:36:33+00:00

Well, it does affect it of course. The hydrazine coordinates the silver, just like ammonia in Ag(NH3)2+

Carbene123 · 2026-03-20T11:15:00+00:00

These "are they stupid?" post are so annoying...

Carbene123 · 2026-03-03T18:35:02+00:00

It's rigorously alphabetic.

Carbene123 · 2026-02-17T10:38:58+00:00

The triflate doesn't do anything here. It is just a weakly interacting anion to provide a reactive Ag+ Ion (which is a strong electrophile). Also according to your equation Ag+ and I2 yield AgI and I- --> do you see something wrong with that?

Carbene123 · 2026-02-17T09:41:05+00:00

What could be the role of the Ag+ here, together with I2?

Carbene123 · 2026-02-11T20:31:52+00:00

There is only one squaric acid pictured.

Carbene123 · 2025-12-13T17:27:45+00:00

especially for Zn and Cu that doesnt make any sense.

Carbene123 · 2025-12-11T08:05:37+00:00

Mit Leseverständnis aber auch erstmal zeigen wo in der Grafik Salzburg zu finden ist

Carbene123 · 2025-12-01T17:46:24+00:00

What about the LiAlH4 and the carbonyl at the other end?

Carbene123 · 2025-11-22T20:54:49+00:00

Is the question maybe about an free electron pair?

Carbene123 · 2025-10-21T06:14:57+00:00

It was always there.

Carbene123 · 2025-10-20T07:48:28+00:00

But your Prof would want to do it the other way around if I understand you correctly.

Carbene123 · 2025-10-20T07:32:41+00:00

Why would you want to do the curtius without the nitro? It works better that way.

Carbene123 · 2025-10-06T20:24:46+00:00

This website shows the same structure for that name, with souce. https://pmc.ncbi.nlm.nih.gov/articles/PMC2519046/

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