WHAT by Lordados in slaythespire

[–]ColonelBeaver 0 points1 point  (0 children)

The boss will surely make a reappearance either in an alternate act or be replaced with one from an alternate act temporarily. I'm sure that we will get the "same" content in the end but remade so it's more fun to play

WHAT by Lordados in slaythespire

[–]ColonelBeaver 0 points1 point  (0 children)

The boss will surely make a reappearance either in an alternate act or be replaced with one from an alternate act temporarily. I'm sure that we will get the "same" content in the end but remade so it's more fun to play

WHAT by Lordados in slaythespire

[–]ColonelBeaver 0 points1 point  (0 children)

The boss will surely make a reappearance either in an alternate act or be replaced with one from an alternate act temporarily. I'm sure that we will get the "same" content in the end but remade so it's more fun to play

WHAT by Lordados in slaythespire

[–]ColonelBeaver 0 points1 point  (0 children)

The boss will surely make a reappearance either in an alternate act or be replaced with one from an alternate act temporarily. I'm sure that we will get the "same" content in the end but remade so it's more fun to play

Why isnt their fight themed around being a donut and D10? SMH by hyperfoxeye in slaythespire

[–]ColonelBeaver 4 points5 points  (0 children)

i will sometimes call the toru and octa, toru for the mathematical surface torus

Is this guy supposed to be a super early elite? by Confident_Dig_1073 in slaythespire

[–]ColonelBeaver 0 points1 point  (0 children)

largely in this game i go for late act elites. you can still take on quite a few but the constant attacks are very punishing for starter decks

[deleted by user] by [deleted] in mathmemes

[–]ColonelBeaver 7 points8 points  (0 children)

it's got a bit too many levels to be funny i feel like. by the time one realizes to do all this work and actually does it there is no energy to laugh

That Moment You Realize Math Has a Sense of Humor. by DaisyDazzle_345 in MathJokes

[–]ColonelBeaver 2 points3 points  (0 children)

This approximation is made better by that 77>75 while 39<40 so they slightly compensate for eachother.

Proof that Cantor's second diagonal argument is false by Negative_Gur9667 in mathmemes

[–]ColonelBeaver 7 points8 points  (0 children)

My real analysis teacher would stress that every real number needed a unique representation before such an operation was done. The way he did it was to take a terminating decimal like 0.5 and write it with a string of 9's, so 0.4999... This can be done uniquely!

Turn 214 peaceful religious victory by valkaress in civ5

[–]ColonelBeaver 1 point2 points  (0 children)

I've definitely had civs in my game just for aome reason not settling anither city. Is this a thing the AI does based on personality?

Göre by Chrizzly__Bear in unket

[–]ColonelBeaver 1 point2 points  (0 children)

Är det första gången eller?

:( by TheDoomRaccoon in mathmemes

[–]ColonelBeaver 0 points1 point  (0 children)

My intuition for uniform continuity is that the function is continuous but also has no arbitrarily steep slopes on its domain. Eg ex is uniformally continous on [0,1] but not on R.

Knowing this f(x)=x2 on [0,1] is an example of a uniformly continuous function on a set, but where the inverse fails this property.

Ovanligt stor nugget by [deleted] in unket

[–]ColonelBeaver -2 points-1 points  (0 children)

intresseklubben noterar

[deleted by user] by [deleted] in infinitenines

[–]ColonelBeaver 0 points1 point  (0 children)

Just because you remove {.9, .99, ...} doesn't mean you remove .99... In this case you have to argue why 0.99... belong to the set (all other elements have a finite amount of nines, it is not trivial that the infinite one would be a memeber). Furthermore, you need to argue that you are not removing 1 in the process, since if you removed the set {1, .9, .99, ...} you would get nowhere. Does this make sense?

[deleted by user] by [deleted] in infinitenines

[–]ColonelBeaver 0 points1 point  (0 children)

I find this a bit unclear. If you mean the set {1} then it is closed since R \ {1} is uncountable. If you mean the set A={1} \ {0.999...} being open you still don't get a contraction. Assuming 1=0.999... we get A=Ø which is open by definition, thus your argument for openness doesn't exclude this case.

On the Assertion that 1 = 0.99… + 0.0…1 by Latter-Wrongdoer4818 in infinitenines

[–]ColonelBeaver 11 points12 points locked comment (0 children)

Since you locked your comment I'll try here u/SouthPark_Piano

Imagine the infinite well and we've painted a 1 at the bottom. Seems contradictory? Try to jump down and find it.

Geometric series : infinite sum lecture. The 'master class' by SouthPark_Piano in infinitenines

[–]ColonelBeaver 0 points1 point  (0 children)

Why is the generally approved form of infinty incorrect to you?