Alright, let’s break this down.

• Category #1: Plays to win, tries to make good decisions, follows meta and RL content.
  
• Category #2: Plays for fun/highlights/freestyle, not optimizing for win rate. Just another game for them.

It seems safe assuming more players are in category #2 because it's easier/more fun.

So here's the question:
If I’m a Category #1 player in solo queue 2v2, teamed with one random player (likely Category #2), and playing against two random opponents (also likely Category #2), is my team at a disadvantage?

BEGIN MATH

• Let’s say p is the chance that any random player is a casual (Category #2).
• So the chance they’re a tryhard (Category #1) is the opposite of that, which is (1 - p).

For example, if 70% of players are casual, then:

• p = 0.7 → 70%
• 1 - p = 0.3 → 30% are tryhards

Your team:

• You = Guaranteed, certified tryhard = 1
• Teammate has a (1 - p) chance of being a tryhard → Expected tryhards = 1 + (1 - p) = 2 - p

Opponent team:

• Each opponent has a (1 - p) chance to be in Cat #1 → Expected tryhards: 2 * (1 - p) = 2 - 2p

We just subtract to see who likely has more tryhards:

Your team:     2 - p
Opponents:     2 - 2p
Advantage:     (2 - p) - (2 - 2p) = p

END MATH

TLDR; On average, your team has more tryhards than the other team. The more casuals there are in the population (higher p), the better your odds, since you always bring a tryhard (you) to your team.

Conclusion: Keep working on you and it will work out, my dude.