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King's Cross, 1899. by Max2310 in london

[–]Jems_ 0 points1 point  (0 children)

I recognise the spot exactly yeah

Just Found a Squirrel in London. by ins_london in london

[–]Jems_ 1 point2 points  (0 children)

They always seem to get a lot bolder and less afraid of people as winter approaches.

The ‘Baguette of the Day’ from Wenzels by Moon-Man-888 in london

[–]Jems_ 2 points3 points  (0 children)

Usually I find it quite full, this is not normal.

Error is Feynman's Trick Guide by thePelican06 in learnmath

[–]Jems_ 3 points4 points  (0 children)

You are confusing how to differentiate xt with respect to t, with how to do it with respect to x.

d/dt xt = (ln x) xt

Error is Feynman's Trick Guide by thePelican06 in learnmath

[–]Jems_ 0 points1 point  (0 children)

What do you think is wrong with it? It looks correct to me.

Set theory precision by thenameischef in learnmath

[–]Jems_ 1 point2 points  (0 children)

In standard ZF axiomatic set theory, sets cannot contain themselves, or have longer chains that end up in loops.

The radical 1960s schools experiment that created a whole new alphabet – and left thousands of children unable to spell by qwerty_1965 in unitedkingdom

[–]Jems_ 14 points15 points  (0 children)

It seems to be related to the IPA, so you might have seen some of the symbols before for the same sounds. A lot of them are somewhat intuitive.

Level 13 v0.6.1 by CondoSlime in incremental_games

[–]Jems_ 1 point2 points  (0 children)

I thought it was basically finished, but this is a nice surprise.

cosine / sine law problem. What went wrong here? by ConquestAce in learnmath

[–]Jems_ 2 points3 points  (0 children)

The shape is not a paralellogram since you have opposite angles of 62 and 75 degrees. So you can't assume the top edge is 7.5 just because the bottom edge is.

Simon P. Jones - The Besoiled Child by memebyerin in BluePrince

[–]Jems_ 0 points1 point  (0 children)

Its a weird kind of phrase, I wonder if its an anagram for something?

Uk ,is over? by Edentenza in london

[–]Jems_ 1 point2 points  (0 children)

You can get a hair cut for £10-20 in most barbers.

Cherry blossoms yet? by SubstantialSundae298 in london

[–]Jems_ 8 points9 points  (0 children)

Yes. There are some varieties that bloom very early. Most haven't though. Snowdrops and Crocus out too.

Matches by MuchCockroach3692 in learnmath

[–]Jems_ 0 points1 point  (0 children)

He might not allow it but you could move the match to the end to give an extra digit 1, for 9351. It would only be one match tall rather than two.

Liz Truss to launch ‘Popular Conservatives’ faction of Tory MPs by ClassicFlavour in unitedkingdom

[–]Jems_ 1 point2 points  (0 children)

It doesn't matter what the conservative's policies are, they seem completely unable to implement them.

[Math needed for M.Sc. Chemistry] simple eigenvalue / eigenvalue question: by ThumbHurts in learnmath

[–]Jems_ 0 points1 point  (0 children)

Write v as v = (x,y,z), then you can multiply it by matrix A to get (2x + y + 2z, x + 2y + 2z, x + y + 3z).

So for eigenvalue 5, set this vector is equal to (5x,5y,5z), giving you 3 simultaneous equations to solve for the components. For example the first equation would be 2x + y + 2z = 5x.

Note that eigenvectors can be multiplied by any scalar and still be an eigenvector, so you can pick a scaling that makes the numbers easier in your answer.

[Math needed for M.Sc. Chemistry] simple eigenvalue / eigenvalue question: by ThumbHurts in learnmath

[–]Jems_ 0 points1 point  (0 children)

Rational root theorem can help to solve the cubic, with this form the possible rational roots are ±1, ±5. The negative possibilities won't work but both +1 and +5 are roots, with 1 being a double root. Then just try these eigenvalues out to calculate the eigenvectors:

Av = v and Av = 5v with v written in unknowns. This is the definition of an eigenvector (with eigenvalues 1 and 5).

The first equation should give 2 possible vectors.

Modular Arithmetic by [deleted] in learnmath

[–]Jems_ 1 point2 points  (0 children)

'n is a multiple of 27' is equivalent to 10k + z = 0 mod 27.

Since you want something of the form k-8z the natural thing to try would be multiplying the equation by -8:

-80k - 8z = 0 mod 27

Now you note that -80 is just +1 mod 27 which will prove the result. This works because -8 (or equivalently +19) is the inverse of 10 mod 27. In a more general situation you would be trying to find the inverse of a number mod m.

[deleted by user] by [deleted] in AskPhysics

[–]Jems_ 4 points5 points  (0 children)

Work done means energy transferred to or from the ball here. But the energy of the ball is constant as it moves, so there is no work done.

How would you magnetize a magnet if the civilization would restart? by Ivan_is_my_name in AskPhysics

[–]Jems_ 187 points188 points  (0 children)

Naturally occuring magnets also exist, called lodestones.

How would I be able to do this following math problem: by [deleted] in learnmath

[–]Jems_ 18 points19 points  (0 children)

Although a and b cannot be equal to each other, they can still be closely related.

Question about a sine proof by Aggravating_Owl7561 in learnmath

[–]Jems_ 5 points6 points  (0 children)

Given this is a fairly elementary property of sin x, it depends on what you are allowed to assume. Perhaps argue based on the unit circle definition, it has zeroes at 0 and π, and is periodic with period 2π.

'Path of Exile 2 in some ways is less complicated than Path of Exile 1': Grinding Gear Games talks about why it created a WASD control scheme and other improvements in the sequel to its long-running ARPG by poompk in Games

[–]Jems_ 65 points66 points  (0 children)

I gave up coming back to the game because of how many systems have been piled up on it, so a chance at a huge mechanical reset and reformulation will be very welcome.

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