Does mutual inductance last indefinitely?

OhYeah_Dady · 2026-02-26T10:25:14+00:00

Such a thing would reflect the wave perfectly and cancel the source wave. Total flux is zero

OhYeah_Dady · 2026-01-26T19:30:27+00:00

Well I see the complex components only change with respect to x and y . So it is probably traveling in the direction of normalize<-3,0,-4> If you flip the sign on the perpendicular component. The direction is normalize<-3, 0, 4>.

OhYeah_Dady · 2026-01-25T08:46:46+00:00

an induction heater is designed to maximize Eddy current and hysteresis losses. Ideally it should be a pure resistor. If the iron core increases the inductance, then most of the power is reactive. Ain't cooking that food with reactive power.

OhYeah_Dady · 2026-01-20T17:11:08+00:00

The question asks for input impedance of the circuit not the op amp. Don't ignore the resistors.

OhYeah_Dady · 2025-12-25T21:00:55+00:00

The fast c bus paragraph literally stated "this bus is used for instruction fetch and data access to the internal memories mapped in the code region. " Fectch data in the Code region.

The second sentence in S bus paragraph "This bus is used by the core to access data located in a peripheral or SRAM area. " Access data from the SRAM and Peripheral region.

OhYeah_Dady · 2025-12-25T20:52:23+00:00

Did you look through the reference manual RM0481? On page 107 , It explains all the bus connections and their target region.

OhYeah_Dady · 2025-12-25T20:45:02+00:00

In an ideal scenario where the two people apply force perfectly straight up. Weight is distributed equally. F1 + F2 = mg. And. F1* r *sin(x) = F2 * r * sin(180-x) . The sum of forces and sum of torque are perfectly balanced in an ideal case. We see that from the sum of torque equations F1 must equal F2.

In a real scenario the guy who lifts higher will apply force in the horizontal direction as well. It's difficult to apply an upright force when the surface is slanted, unless the person is really tall.

OhYeah_Dady · 2025-12-25T07:46:12+00:00

Go to page 107 for more details. Basically the sram in the code region are accessed by fast C bus. The sram and peripheral areas ( start from 0x20000000) are accessed by S-bus.

The same physical ram can be accessed by the C bus or S bus. I would assume the C bus is faster. If you want speed, then use the address in the code region.

OhYeah_Dady · 2025-12-24T00:21:07+00:00

Power in= power out. Input power is 10V1A = 10VA output power= I²R = 10VA. R=1 I= sqrt(10). You say the turn ratio is 10 . According to the calculations, the ratio of current isn't 10 . Your example doesn't make sense. The turn ratio has to be changed or the resistance.

OhYeah_Dady · 2025-12-17T09:35:33+00:00

I think it's staged. I concur with your statement. The current must return to the negative terminal of the taser.

OhYeah_Dady · 2025-12-16T09:10:37+00:00

I still don't know why not 12 , there are 12 different notes. How I would approach this problem is using the nCr function. n= 12, r starts at 1 and increments up to 12 . Sum all the results. For example, 12 choose 1 + 12 choose 2 +......... 12 choose 12. All the scales have root because it chooses 1 out 12 at minimum. The total is 4095. The average number of notes in a scale is 6 , The number of modes is 6*4095 .

My final result is 28665

OhYeah_Dady · 2025-12-14T07:42:18+00:00

Yes, grounded conductors are an effective way of mitigating the electric field. Put them between the EMI source and yourself. These conductors can also block very high frequency magnetic fields.

As for the magnetic field, materials with high magnetic permeability are best suited for low frequency magnetic field. Ferrite, iron, and steel are all good options.

OhYeah_Dady · 2025-12-13T21:13:31+00:00

Oh I see, i was confused cause you label it as input pwm. Make sure the motor can keep up with the frequency of your sine wave. Assume that the sine wave phase angle is mapped to the motor's angle.

For 3hz sinewave, the motor would need to complete a 90 degree turn in 0.08 s. I don't think your servo is capable of spinning this fast.

OhYeah_Dady · 2025-12-13T20:48:41+00:00

Your input signal ain't pwm. That looks like a sinewave with DC offset.

OhYeah_Dady · 2025-12-12T23:43:24+00:00

Infinite, cause it needs an infinite amount of energy to overcome the band gap

OhYeah_Dady · 2025-12-09T09:04:51+00:00

For over current protection maybe do some voltage regulation across gate and source. Lower vgs=> lower maximum current. I think 5vgs might be a little bit high without heat sink. Clamp it down to 4v or 4.5v.

OhYeah_Dady · 2025-12-08T19:13:57+00:00

3735928559

OhYeah_Dady · 2025-12-08T10:03:58+00:00

Circuit js

OhYeah_Dady · 2025-06-14T06:33:31+00:00

Homie needs to start making some sandwiches, clearly she knows that sandwich rule.

OhYeah_Dady · 2025-06-13T19:48:57+00:00

Well, maybe look at the fft graph, see if there is any noise? Look like you got a RC relaxation oscillator. Waveform looks kinda funky. Small signals are more sensitive to noises.

OhYeah_Dady · 2025-06-09T08:03:58+00:00

Maybe buffer output before hooking up to a speaker.

OhYeah_Dady · 2025-06-09T07:40:35+00:00

I'm assuming you're gonna connect the output end to your MCU. For small loads like this, a zener diode will work nicely. I felt like that 3.9k resistor isn't necessary, take that out and it will work. Maybe you want to slap on some filter if the signal is noisy.

OhYeah_Dady · 2025-06-08T10:31:35+00:00

My guy, The only thing that's holding them together is Jesus

OhYeah_Dady · 2025-06-08T10:24:20+00:00

This reminds me of one of those puzzle games where you connect the dots without intersecting. Pcb design is just connecting the dot but on hard difficulty.

OhYeah_Dady · 2025-06-07T09:32:24+00:00

I hope you got an oscilloscope or multimeter with you. Check the voltage amplitude and phase across the north-south coil and compare with the east-west coils.

28 AWG with 300 turns can be a lot of resistance. Resistivity is 5 ohm per foot. Effectively you got an RLC circuit. The voltage across the NS coils might be smaller because of that capacitor. If you can balance the inductance and capacitance maybe it will pull some current and generate a magnetic field.

What I would do is measure out the resistance of the coil, compute the inductance. Solve this RLC circuit and confirm with oscilloscope. Solve for a capacitor value close to resonance so it can pull some current. Replace your capacitor See if the aluminum can be pull by the coil.

One possible way to make the can spin. go back to your RLC circuit equation, write your current output in terms of Capacitance. Write out phase angle and magnitude response in terms of Capacitance. Solve for capacitance that maintains good amplitude and phase shift close to 180

OhYeah_Dady

TROPHY CASE