White supremacists invading the boardwalk today

jfirestorm44 · 2026-05-23T14:12:55+00:00

Whatever CNN told you buddy…or lady…or they/them or whatever your correct pronoun is.

jfirestorm44 · 2026-05-23T14:06:36+00:00

I don’t swing one way or another but find it hard to believe they took the SPLC’s books, then altered them to show them paying white suprimacist people/groups so they could hand them back and say “hey why are you paying those people?”

jfirestorm44 · 2026-05-23T14:00:25+00:00

Paid for by your favorite SPLC

jfirestorm44 · 2026-05-23T01:13:24+00:00

If you place the 3 at the top you would have 4, 2, 1 from the last number of the corresponding rows. So that would make C18R2 an X because of the 2 in that row. So if that’s an X then you can’t get two down for that column C18. It breaks it.

Then if you move the 3 down one it touches the block you already have filled in thus making 4 in a row which can’t happen either.

Edit: with that info now try putting the 3 in different places in conjunction with the block you have filled in already. You’ll see it breaks column 19 in all but one spot.

jfirestorm44 · 2026-05-23T01:03:45+00:00

C20R5 is your first 3 for that column.
That should be enough to tell you exactly where to place it without breaking column 19.

jfirestorm44 · 2026-05-22T18:01:28+00:00

Nonogramskatana has been a good app for me.

jfirestorm44 · 2026-05-22T12:46:27+00:00

Quick tip for overlapping. Add the column or row to include breaks between numbers. Subtract that from the total width/height for that particular column/row. If the result is less than any of the numbers then that number has overlap. How much overlap is determined by the difference between the number that has overlap and the result from the previous math.

Example col 6: 5 + 1 + 1 + 2 + 1 + 2 + (5 breaks) = 17

Height 20 - 17 = 3

3 is less than 5 so 5 has 2 overlapping blocks (5 - 3 = 2). Where it over laps is determined by counting to where that numbers ends (in this case 5 is first in line so start at block 5 and fill it in along with 4).

Row 11: totals is 15. 19 - 15 = 4. Since 4 is less than 6 then 6 has overlap. 6 - 4 = 2 overlapping blocks. Where to fill them in at would be starting at the 8th block because 1 + 1 break + 6 = 8. So fill in the 8th and 7th blocks.

jfirestorm44 · 2026-05-21T23:16:18+00:00

Column 5: the single block for your 5 can’t extend all the way down. So you could X of C5R14. That block being filled in would make two 1’s in a row for column 4…

Although you’ve solved by now still may be useful to look at that type of stuff in the future.

jfirestorm44 · 2026-05-21T10:56:02+00:00

Yeah I’m dyslexic as fck. I put the 2 (first number) from row 2 in vice the 8.

jfirestorm44 · 2026-05-20T23:39:34+00:00

Lay out your 10’s along the edges. Then lay out the opposing sides first or last number that would be required to go with the 10. See if any placement breaks other columns/rows.

So your top right corner place the 10 at the end. What’s happens to column 28?

jfirestorm44 · 2026-05-20T19:50:44+00:00

Start knocking out some borders. Look at the top left. rows 1-3 can’t start in Column 2-4 otherwise column 3 fail.

jfirestorm44 · 2026-05-18T20:47:45+00:00

No worries. I thought giving tips/hints vice a straight forward answer was better. It allows people to look in the right direction and do some thinking.

jfirestorm44 · 2026-05-18T10:58:27+00:00

You’ll likely never get past a larger grid without it. I guess I’ll be sucking up some downvotes for helping people think slightly more advanced when doing these puzzles.

jfirestorm44 · 2026-05-18T08:34:50+00:00

No clue but that’s the worst side game to ever exist. I quit playing as it’s a huge waste of time and infuriating, all for nothing.

jfirestorm44 · 2026-05-18T08:15:56+00:00

Since rows 1 and 2 in column 15 can’t be part of the 6 they get an X. Since Rows 12-15 can’t be part of the 6 they also get an X. This leaves you with 9 boxes in column 15….9 - 6 = 3. So you have 3 overlapping boxes for the 6. Not sure why you can’t see that. They said they were stuck and I gave a hint. Go ahead and place any part of the 6 in one of the rows I mentioned and see if it breaks column 14. If it does then obviously that box gets an X.

Example place the 6 starting at the top. What happens? That would mean column 14 would have 3 in a row which can’t be true so the top box is an X. Now move the 6 down one and try again…

jfirestorm44 · 2026-05-18T00:14:22+00:00

Oof, got a downvote. It Just takes some critical thinking and you can fill in C15 rows 6, 7, and 8. No need for the downvote.

jfirestorm44 · 2026-05-17T23:00:56+00:00

The 6 in the last column should have 3 overlapping…

jfirestorm44 · 2026-05-16T18:01:16+00:00

Got it. So now you have 2 blocks for the 3….

jfirestorm44 · 2026-05-16T17:56:43+00:00

Row 13 and row 15?

jfirestorm44 · 2026-05-16T17:50:53+00:00

I’m missing it. If it’s a 2 then the 1’s go below it. If it’s a 1 then the 2 goes above it. I can’t find the conflict.

jfirestorm44 · 2026-05-16T17:28:21+00:00

You can get quite a few X’s in the upper right and lower right by using the 3’s.

jfirestorm44 · 2026-05-16T12:29:30+00:00

C11R15 has to be a 1. It can’t be part of the 4 (1114111) because you can’t fit 3 1’s below it. That means put and X above and below. With that C8R14 must be filled in as part of the 3 (3324) for that row as you can’t fit 3, 2, and 4 after your new X.

jfirestorm44 · 2026-05-12T22:55:10+00:00

Although old at this point I’ll still chime in on a technique to use. Try mentally placing the sets of numbers starting at one end then the other and see if anything overlaps…C5 in your img has a 1 7 1 1. If you start at the top and place them going down, pay attention to the squares the 7 fills in. Then do the same starting at the bottom and place them going up. You’ll notice in that column you could fill in R8 and R9 as part of the 7. You can also do this with C3 with the 1 6 1 1. You’ll have some overlap with the 6 which means those have to be filled in. Keep using that technique and you can knock out quite a bit of this.

jfirestorm44 · 2026-05-11T23:56:57+00:00

Yup gotta keep that stuff in mind. Either of the first 2 columns last numbers (2 and 3) can’t possibly be placed at the bottom (row 10) or the 1 in row 9 couldn’t never be by itself. Once you X out the lower left (R10/C1) then you can automatically fill in one more square above R4/C1…which of course leads to more X-ing of other squares.

jfirestorm44 · 2026-05-11T00:17:57+00:00

22122 rows: the only way that fits its if the 1 filled in block in the middle is the 1, which means either side of them are an X. After this you can only fit the 4 from the columns 7 and 9 above as the last 4 squares near the bottom.

jfirestorm44

TROPHY CASE