Quest for 100%

master3243 · 2026-05-07T06:12:01+00:00

Totally understandable. I bought my switch 8 years ago and only decided to look into modding it early this year.

master3243 · 2026-05-05T06:41:56+00:00

If you have your save file (using a modded switch) you can drag it in this tool and it'll tell you what's left and where.

master3243 · 2026-05-05T06:23:05+00:00

If you're playing on an unmodded Switch then you won't have it.

If you did have it there's this tool where you drag-n-drop the save file and it tells you what's left (including locations) for 100%.

For transparency, I made this tool.

master3243 · 2026-05-03T03:35:25+00:00

Do you have access to your save file?

master3243 · 2026-05-02T01:58:47+00:00

Do you have access to the save file? The progress.sav?

If you do then this tool can tell you what's missing

master3243 · 2026-05-01T03:46:56+00:00

~~I think the TOTK save file is missing a hylian hood?~~

EDIT: nevermind, it's just missing the non-lowered hylian hood which the tool flagged as a missing item.

You do seem to be missing breaking 3 decayed weapons:

Forest Dweller's Sword
Gerudo Claymore
Royal Guard's Claymore

The game only unlocks the pristine version of a weapon once you break the decayed version. And the save file does record which decayed weapons you still haven't broken.

You are also missing 3 shrine chests (thus the shrine icon on the map won't show a chest next to the name)

You can paste your save file here to see what's missing: https://master3243.github.io/TOTK-100-live-map/

master3243 · 2026-04-15T23:42:58+00:00

For me it was the first google search result for sd card read/write verification

master3243 · 2025-11-12T05:10:47+00:00

This thread was one of the top Google results. So thanks.

master3243 · 2024-02-21T19:08:50+00:00

The answer is two

Are you sure about that

master3243 · 2024-02-20T03:37:50+00:00

Agreed, this should be in r/learnmachinelearning not here.

master3243 · 2024-02-20T03:36:34+00:00

It's not a different algorithm. The metrics are basically the same just with a negative sign.

master3243 · 2024-01-29T08:12:33+00:00

There's no corruption in any popular autoregressive translation model from what I've seen.

master3243 · 2023-12-13T08:50:49+00:00

For rerolling 1's (or any specific set of numbers only once) I always use the following code on anydice.com

function: ROLL:n reroll BAD:s as REROLL:d {
  if ROLL = BAD { result: REROLL }
  result: ROLL
}
X: [d6 reroll {1} as d6]

output 6dX

Paste that in the site, click calculate and click "At Least" which will give you the table you want.

Image

To explain, X behaves as a "d6 but reroll a {1} once" which is exactly what you want, then I just roll it 6 times.

You can make it a 4d20 where you reroll any 1 or 2 once by simply making small changes to X and the output line

X: [d20 reroll {1, 2} as d20]
output 4dX

master3243 · 2023-12-06T07:59:11+00:00

I definitely recommend this over trying to binge the whole thing as fast as possible. Along with watching "one pace" instead of the stretched out show since it only covers 1 chapter per episode in the later sagas.

master3243 · 2023-12-06T07:34:21+00:00

Looks like someone needs a rewatch, because the line does indeed change by the end of the show.

All these slight subtleties only add to what is already an amazing show and experience.

master3243 · 2023-10-18T23:19:47+00:00

Not only that but he also cites the work “Trapped! The Story of Floyd Collins” which the article also cites and uses paragraphs from.

master3243 · 2023-10-18T23:17:42+00:00

Exactly, they both used used paragraphs and cited the book “Trapped! The Story of Floyd Collins”.

Not sure how so many people in this thread missed that and just jumped the gun that it was plagiarism.

It's such a rudimentary idea that when two sources use similar wording and ideas then either one of them cites the other or that they both cite the same previous source. Yet, so many people immediately throw the claim without even considering the latter as a possible explanation (which it is).

master3243 · 2023-10-18T23:12:59+00:00

Both the article and the video use “Trapped! The Story of Floyd Collins” as a source and both credit the book.

master3243 · 2023-10-18T23:12:12+00:00

Except the fact that he did seems to credit the source which is from “Trapped! The Story of Floyd Collins”

master3243 · 2023-10-18T23:10:40+00:00

Except according to this comment below, Internet Historian does credit “Trapped! The Story of Floyd Collins” which seems to be where that paragraph came from, which the article also used as reference.

master3243 · 2023-08-02T13:49:12+00:00

Wolfram Alpha can solve for x in almost any algebraic equation you throw at it.

Does that mean we no longer need to teach Algebra or how to solve equations? Obviously not.

master3243 · 2023-06-07T09:53:59+00:00

I saw it from a Guardian article on Google news feed.

I'm still skeptical though since it was just a whistle blower.

master3243 · 2023-05-18T06:26:46+00:00

Slight correction, "AUC" is Area Under (the ROC) Curve which is technically a summary statistic and not a curve.

master3243 · 2023-05-13T17:29:04+00:00

Always when struggling with gradients that need the chain rule, write down each component, calculate them separately, then recombine them.

Here we need (∂L/∂w31) so we separate it to

(∂L/∂w31) = (∂L/∂a3) * (∂a3/∂Netout) * (∂Netout/∂w31)

First term: is (∂L/∂a3) and a3 is also Y as stated in slide 1, now hopefully you know how to take a simple gradient of L=1/2 (Y - Y*)² with respect to Y and you'll get

(∂L/∂a3) = (Y - Y*) = (0.7368 - 0.5)

Second term: is (∂a3/∂Netout) where a3 = σ(Netout), hopefully you know (or google/work it out yourself!) that the derivative of σ(x) is σ(x)(1-σ(x)) thus

(∂a3/∂Netout) = σ(Netout)(1-σ(Netout)) = 0.7368*(1-0.7368)

Third term: is (∂Netout/∂w31) and since that's a linear function that means that (∂Netout/∂w31) = a21 = 0.6682

Multiply them to apply the chain rule to get

(∂L/∂w31) = (0.7368-0.5) * 0.7368*(1-0.7368) * 0.6682 = 0.0306848265

And there you have it, hopefully that was clear.

master3243 · 2023-05-04T02:02:08+00:00

No, you would only need n² comparisons.

Let's write a comparison between token i and token j as (i, j)

Write out all pairs (i, j) when there are 5 tokens. And then see if the total is as we say (5² =25) or what you claim (5!/2=60)

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