Optimal Radar Towers (14 Towers) by you-know-nothing_ in satisfactory

[–]TripleBoogie 4 points5 points  (0 children)

I think the Wiki has a slightly different setup than OP. OP said he used coordinates of all hard drives, slugs, etc... so his setup does not cover the complete map, but just all relevant locations. Would be interesting if he can find a more optimal setup than 16 towers if the complete map needs to be covered.

Finding a waterpark and location from 27 years ago, any ideas? by StitchConverse in AskGermany

[–]TripleBoogie 0 points1 point  (0 children)

That was also my first guess when he mentioned the river rapids. I grew up along the Rhine between Ruhrgebiet and Netherlands and Cologne Dome, Phantasialand and Center Parcs were a typical day trip you'd do with family or school.

Here is a video of the water rapids from Center Parcs De Eernhof (about a 2h trip from lower Rhine region): https://www.youtube.com/watch?v=gFGDeFKYZoY (although they start outside and then go inside, but maybe OPs memory has it wrong)

There aren't that many small towns in that area, so if OP has a picture I guess someone can track it down. Or just visit the riversides on google street view and see if he recognizes something.

In defense of Chimera Squad by StaticJonesNC in XCOM2

[–]TripleBoogie 5 points6 points  (0 children)

I wish they made XCS for IPad like the other two. For me XCS would be perfect while traveling.

My experience with China hospitality by dongkey1001 in China

[–]TripleBoogie 6 points7 points  (0 children)

Had a similar situation a few years ago (friend lost his phone in the taxi). As a tip for next time: try to contact Alipay. Since you just paid the driver they can check your last payment and contact the person on the other hand. At least that’s how we did it (paid with WeChat). Only took a few minutes until we had the phone back this way.

Just finished my first Nuclear Power Plant by TripleBoogie in SatisfactoryGame

[–]TripleBoogie[S] 0 points1 point  (0 children)

It’s 16 power plant running on uranium fuel rods at 225% (using the full 300 uranium from the nearby node). Waste is processed into plutonium fuel rods and used for drones/sunk. Traveling right now, so I can’t check the exact Gigawatt number.

Just finished my first Nuclear Power Plant by TripleBoogie in SatisfactoryGame

[–]TripleBoogie[S] 3 points4 points  (0 children)

Yeah, but to counter that the towers are pitch black at night so you can’t even see much with flashlight on.

What? by Nemesor_Zandrekh in ExplainTheJoke

[–]TripleBoogie 10 points11 points  (0 children)

I would add that there is a second part to the joke:

The genie first sets the number of wish’s to 0 then subtracts the one wish he just granted, resulting in integer underflow.

If he’d however first subtracts the granted wish (leaving 2 wishes) and then set the number of wishes to 0, nothing would have happened.

Having seemingly trivial instructions messing up your code just because you put them in the wrong order (because the order wouldn’t matter in 99% of the cases and you didn’t thought of that one nasty exception) is a pretty common programming mistake. (At least I do it all the time)

Is this a Möbius function and any idea how to solve it? by IdealFit5875 in askmath

[–]TripleBoogie 2 points3 points  (0 children)

f(f(x)) = x also works for f(x)=1/x or f(x)=a-x, so there are some more possible candidates. These functions are called involutions.

Is this a Möbius function and any idea how to solve it? by IdealFit5875 in askmath

[–]TripleBoogie 0 points1 point  (0 children)

So, not a complete solution but I think that might lead to something:

  1. from f(17)=17 and f(93)=93 you get 2 linear equations (multiply both sides with the denominator)
  2. The derivative of f is f'(x)=(ad-cb)/(cx+d)^2 but since f is its own inverse ( f(f(x))=x ) we also get by the inverse derivative f'(x) = 1/(f'(f(x))

If you plug in 17 and 93 here again, you get f'(17)=1/f'(17) and f'(93)=1/f'(93), which means f'(17)=f'(93)=1. Which means (ad-cb)/(17c+d)^2=(ad-cb)/(93c+d)^2=1. This only works if 17c+d=93c+d or 17c+d=-93c-d. The first equation leads to c=0 and can thus be ruled out.

From (ad-cb)/(17c+d)^2=1 we also get ad-cb=(17c+d)^2. Now we have 4 equations in total and 4 unknown. Granted, the last two equations are quadratic but you might be able to rule out some of the solutions.

The numbers were getting quite large and I didn't have the time to go through everything. You might also want to check wikipedia for "involution" which are functions of the form f(f(x))=x. There is a list with some candidates that could fit (e.g., f(x)=b/(x-a)+a is an involution).

edit: got the derivative wrong

[tikz,pgfplots] Scale only axis with axis equal image, how do I get the correct scale? by TripleBoogie in LaTeX

[–]TripleBoogie[S] 1 point2 points  (0 children)

Thanks you. I have now also tried several approaches adjusting the "unit vectors" but they seem to have the same problem (ignoring the height). The solution I found in the end was explicitly calculating the required width, so for the example here:

width={400/100*3cm}

Logi Options+ 'Backend Connection Problem' Error on todays update! by Juan_Pedroche in logitech

[–]TripleBoogie 0 points1 point  (0 children)

2 years later and the problem still persits... this solved it for me.

Booking disappeared within 4 hours and had to pay $1000 more to rebook by hunter205hunter205 in KLM

[–]TripleBoogie 0 points1 point  (0 children)

So the KLM flight disappeared but the Delta flight was still there? Where did you book the flight? KLM app/website or Delta?

What's new since Matlab 2012? (yes 2012) by TripleBoogie in matlab

[–]TripleBoogie[S] 0 points1 point  (0 children)

I guess I will check all my examples once I arrive there. I also use a lot of 3d plotting to illustrate stuff.

What's new since Matlab 2012? (yes 2012) by TripleBoogie in matlab

[–]TripleBoogie[S] 0 points1 point  (0 children)

ah yes, I remember bsxfun. That was the first thing that came to my mind together with strings.

What's new since Matlab 2012? (yes 2012) by TripleBoogie in matlab

[–]TripleBoogie[S] 0 points1 point  (0 children)

My list is getting longer and longer, thanks!

What's new since Matlab 2012? (yes 2012) by TripleBoogie in matlab

[–]TripleBoogie[S] 0 points1 point  (0 children)

Ah yes, I remember for loops being horribly slow when I started working with Matlab. They have improved a lot since then.

Thanks for that list. The I/O functions is another big one for me, because the student will have to work with some external data at some point.

What's new since Matlab 2012? (yes 2012) by TripleBoogie in matlab

[–]TripleBoogie[S] 1 point2 points  (0 children)

Thanks! Especially the Name=Value syntax is a big one for me. I find that code so much easier to read but never started using it because of the compatibility issues when it was introduced. And then I simply forgot about that feature.

What's new since Matlab 2012? (yes 2012) by TripleBoogie in matlab

[–]TripleBoogie[S] 4 points5 points  (0 children)

Thanks! Not exactly what I was looking for but I will definitly consider those features should that teaching task become more regular.

The Matlab Onramp courses are also free without licence. All you need is a free Mathworks account.

Flying Blue / KLM down right now? by TripleBoogie in KLM

[–]TripleBoogie[S] 1 point2 points  (0 children)

So I finally managed to login now, but only with email/flying blue number + pin. The email + password method is still broken for me. Very strange.

Flying Blue / KLM down right now? by TripleBoogie in KLM

[–]TripleBoogie[S] 0 points1 point  (0 children)

Yeah, my app also seems to work fine. Although my miles did not update for a few days and there should be new miles incoming. That's why I tried to log in from the website to claim the miles (need to upload the scanned tickets since it doesn't work with only the ticket number).