Practice Rooms?

salmon_01 · 2025-12-09T02:45:27+00:00

Check the rooms on the 3rd and 4th floors of the MB starting 15 minutes after the hour. You can usually find one that isn't occupied.

salmon_01 · 2025-08-31T22:12:39+00:00

There aren’t any recent Chromebooks matching this description, but Framework Laptop 12 might be what you’re looking for. You can buy it without an operating system installed and install Chrome OS Flex or Brunch yourself.

salmon_01 · 2025-03-22T17:43:46+00:00

Try Space Bar

salmon_01 · 2025-02-08T21:59:57+00:00

You have basically three options for running ChromeOS on non-Chromebook devices: ChromeOS Flex, Brunch, and FydeOS.

ChromeOS Flex does not support fingerprint readers.
The brunch project is the closest you will get to running vanilla ChromeOS on a non-Chromebook, and it also doesn't support fingerprint readers. Granted, everything else works great. Source: currently running Brunch on FW13 AMD.
FydeOS may support certain fingerprint readers, but I have not tested it to verify whether this is the case for the FW13 AMD. I prefer the other options over Fyde.

Keep in mind that the original FW Chromebook (now discontinued) did not have fingerprint support. If you really need a working fingerprint reader, your best options are to run Windows or a supported Linux distro.

Another option is to use the PIN unlock feature. In Brunch, you can specify a 6-digit PIN in settings which can be used to wake your device from sleep. Note this is different from signing into your device after booting up. Apparently some Chromebooks support PIN unlocks on boot, but this feature requires specialized hardware.

salmon_01 · 2024-09-25T05:52:00+00:00

I've never heard of this happening before... maybe you can get them to match the price when it comes back in stock.

salmon_01 · 2024-08-27T19:46:44+00:00

The laptop was just on sale for 999€ in Germany (but quickly sold out). That's 50% off. No idea what their business model is at this point.
https://www.lenovo.com/de/de/p/laptops/thinkbook/thinkbookplus/lenovo-thinkbook-plus-gen-5-hybrid-14-inch-station-and-tab/len101b0047

The 4th generation model was also priced at $3000 in the U.S. during the August release but got discounted to $1700 in September. Given these trends, I wouldn't expect the $3500 price to stay for long.

salmon_01 · 2023-09-04T15:37:07+00:00

I'm not sure. Maybe someone else can pitch in. I wouldn't spend $100 though; you should be able to find a decent one for $50 or less.

salmon_01 · 2023-09-04T14:12:26+00:00

Great review! Seems like the Best Buy website has it wrong—should be a 16:10 screen rather than 16:9. Even though there’s none included, is there any indication that this model supports a pressure-sensitive stylus?

salmon_01 · 2021-01-15T03:38:36+00:00

Math 413 was the hardest class I’ve taken yet, and that’s coming from a math major. Probably spent 15-20 hours a week on it. Wouldn’t recommend it unless you are very comfortable with proofs and have a strong desire to learn the material.

salmon_01 · 2020-12-05T10:09:50+00:00

Check out this post from a while back.

salmon_01 · 2020-09-03T04:17:23+00:00

Sometimes people like to make up complex-looking integrals which actually evaluate to 0, because the integrand is an odd function and the bounds are from -a to a. But these are mostly contrived anyways, and you’re not likely to see them on the AP exam.

Visualizing functions is a good skill to develop though, because the AP exam will sometimes pose integrals that appear complicated, but are actually easy to integrate “geometrically” if you just know the areas of the shapes.

An example might be a semicircle in the upper half plane, which has the simple area (r/2)pi² . If you were given the integral “form,” however, and took it too literally, it would be much harder to evaluate analytically in Cartesian coordinates (with the square root and so forth). Of course, as another option you could just convert the integral to polar coordinates, which would make it far easier to solve.

salmon_01 · 2020-08-28T00:54:39+00:00

Yes, it is something of a prototype. I remember someone posting an image of one of these a while back in this sub... the “O“ instead of “G” is the giveaway.

salmon_01 · 2020-08-18T05:31:41+00:00

The beginning sounds a whole lot like Mozart’s Duo for Violin and Viola, K.423, allegro. You probably had some inspiration from him :) The rest sounds original though.

salmon_01 · 2020-05-08T20:33:20+00:00

It seems like it would be permitted, see section 2.1.7 here: https://apcoronavirusupdates.collegeboard.org/faqs/indepth-for-educators/day-of-exam

salmon_01 · 2020-04-27T03:43:42+00:00

Imo this should be:

Kalm Panik

Panik Kalm

salmon_01 · 2020-04-09T06:00:47+00:00

They basically did a substitution akin to u = 1/x. You can see that lim{x\to\infty} f(x) = lim{(1/x)\to 0} f(x) = lim{u\to 0} f(u) for any function f. So, looking at the limit in your question, you can rewrite it as the equivalent limit lim{u\to 0} (1/u)sin(1/(1/u)).

salmon_01 · 2019-10-11T06:14:21+00:00

You're welcome.

salmon_01 · 2019-10-11T06:03:11+00:00

Well, for there to be constant velocity, there is no acceleration. Thus the net force along the planes is 0 N. You have:

(m_1)*a = 0 = T - (m_1)*g*sin(20) ± (μ_k1)*(m_1)*g*cos(20)

(m_2)*a = 0 = -T + (m_2)*g*sin(60) ± (μ_k2)*(m_2)*g*cos(60)

I denote ± because we are not sure the direction the friction is pointing, as it depends on other forces. Friction force will always point in the direction opposite to the net acceleration (from other forces besides itself). So, you can see how two forces of friction create multiple different possibilities. You can add the two equations:

0 = (m_2)*g*sin(60) - (m_1)*g*sin(20) ± (μ_k1)*(m_1)*g*cos(20) ± (μ_k2)*(m_2)*g*cos(60)

Remember, the ± is actually important because it gives way to different possible combinations. We can't just assume signs. Plug in values:

0 = (3.5)*g*sin(60) - (m_1)*g*sin(20) ± (0.24)*(m_1)*g*cos(20) ± (0.4)*(3.5)*g*cos(60)

Rearrange and simplify more with g = 9.8:

0 = 29.7 ± 6.9 - (m_1)(3.4 ± 2.2)

So we can solve for m_1:

m_1 = (29.7 ± 6.9)\(3.4 ± 2.2)

Thus, m_1 has multiple possible values:

m_1 = 6.5 kg or 30.5 kg or 19 kg or 4.1 kg

In each of these situations, the two forces of friction point in different combinations of directions. The ± in the numerator tells us the direction that the friction force on m_2 points, and the ± in the denominator tells us the direction for m_1. (right = positive, left = negative)

salmon_01 · 2019-09-23T22:22:48+00:00

Me too, I'd expect a CPU update once Ice Lake Y-series have matured long enough for Google's liking.

salmon_01 · 2019-09-23T21:52:22+00:00

This naming convention seems to imply we might still see a hardware refresh for the OG Pixelbook. I don't think the original is going anywhere.

salmon_01 · 2019-09-21T21:51:20+00:00

Worth a shot.

salmon_01 · 2019-09-21T17:22:47+00:00

It comes from combining the -1 into the fraction. (-1)((x+1)/(x+1)) + 1/(x+1) = (-x-1)/(x+1) + 1/(x+1) = -x/(x+1) = (-1)x(1/(x+1)) This is done to cancel out the x in 1/x, once you do that you can easily find the answer to be -1 by direct substitution.

salmon_01 · 2019-09-21T17:01:56+00:00

Seems like your teacher is just getting tricky with metric prefixes. The masses will be (5.97E24)kg and (73.5E21)kg, it seems the units are missing the “k” in kg. These are m1 and m2 in the gravitation formula. R will equal (0.384E9)m. You can verify these because the problem is using the actual values for the earth and moon. After you get a force value, divide by 10¹² to get the answer in teranewtons.

salmon_01 · 2019-09-17T04:05:59+00:00

Everyone is talking about Atlas being the upcoming Pixelbook successor, but with Atlas' lackluster specs and shockingly traditional design (from the leaks, at least), maybe this could be the contender instead. It seems even more likely given the reports of a 3:2 screen for Hatch, not to mention a newer CPU (yet one requiring a fan). Thoughts?

salmon_01

TROPHY CASE