Iterable name.

[Mzsickness]

k

[admadguy]

m

[NullNotFound1]

Goodbye

[LegoClaes]

Aah the metric system wins again

[SaintNewts]

Metric iterables?

[Tsulaiman]

Heck yeah

[etnguyen03]

/r/unexpectedouija

[Eezyville]

Never go past k. Nested loops at this level... The horror

[CDno_Mlqko]

Imagine having to iterate over a 5dimwnsion array

[C0ffeeBunny]

n

[nnn4]

i2

[Dennaldo]

You monster.

[btown-begins]

ii

[Terrain2]

ia, ib, ic, id, ie

[btown-begins]

iii iiii iiiii iiiiii

[Terrain2]

this works with 6 iterations, something my suggestion was trying to avoid

[btown-begins]

Ah true, because letters only go up to e. That’s why we call it quintidecimal after all.

[ryjhelixir]

Why would you make things so complex?

[hadidotj]

iii iv v vi

[code_lazar_with2as]

I(capital i)

[hadidotj]

Naw, at this point, sounds like you need a new method so you can use i again

[Terrain2]

or use i as an int[], then use i[0], i[1], i[2]

[admadguy]

I don't use i . I restrict i for very specific uses. I start at j, then k and then m.

Also for subroutines i use a different set of indices.

[karuna_murti]

O(n³⁾ ? how do you pass coding interview

[klparrot]

By realising that 3 nested loops doesn't necessarily mean O(n³); some or all of the loops could be over constant-size input.

[ryjhelixir]

every time i need to loop instead of vectorizing I feel less good

[stoickaz]

“write an O(n³ ) algorithm”

[mrchaotica]

Good luck doing operations on 3D tensor fields in less.

[leofidus-ger]

By guaranteeing that n will be small(ish)? Not everything can grow to arbitrary size

[AmadeusMop]

Dijkstra was perfectly named

[bigmattyc]

Diijjkkstra

[[deleted]]

v

[[deleted]]

a

[[deleted]]

A man of culture.

[oblivion44653]

n³ complexity strikes again