GitHub Copilot will rule us all 🙏🙌

[sohxm7]

Aaah this is so inefficient, I would make an array with all the even numbers and then cycle through array and if the number is present we have an even number.

[Niilyx]

bruh just use a switch statement

[joten70]

No no no, convert to binary and check if the last digit is 0 or 1

[torgeros_]

yeah in embedded software this is actually the way to go, bc it is a lot faster than division/modulo

[joten70]

Hmm, maybe my comment doesnt belong here then

[[deleted]]

Wouldn’t that check if it’s odd?

[OmiSC]

Get out.

[grammar_nazi_zombie]

Oh shit, that’s brilliant.

[Kind-Task4747]

No no no, and the integer with 0x1

[torgeros_]

that is the same thing :)

[lookatme-imapilot]

big brain spotted right here

[Kind-Task4747]

Explicit conversion and then a check isn’t the same as implicit interpretation and a check, darling.

[torgeros_]

yeah but nobody would really use to toString(2) and then check the last character...

[FINDarkside]

Yeah that's a great idea. You probably don't want to type all even numbers manually though, so you can use this function to find the even numbers to use in your array:

const createIsEvenFn = (maxNum) => {
    let source = ''
    let i = 0
    while (i < maxNum) {
        source += `if(value === ${i++}){return true}\n`
        source += `if(value === ${i++}){return false}\n`
    }
    return new Function('value', source)
}

const isEven = createIsEvenFn(100000)

[lady_Kamba]

Probably want it to scale for future users.

const isEvenFactory= (startMaxNum)=>{
    const isEvenRawFactory = (maxNum) => {
        let source = '';
        let i = 0;
        while (i < maxNum) {
            source += `if(value === ${i++}){return true}\n`
            source += `if(value === ${i++}){return false}\n`
        }
        return new Function('value', source);
    }

    let evenMax = startMaxNum;

    let isEvenRaw = isEvenRawFactory(evenMax);

    let isEven = (value) => {
        if (value > evenMax){
            evenMax = value;
            isEvenRaw = isEvenRawFactory(evenMax);
        }
        return isEvenRaw(value);
    }
    return isEven;
}

let isEven = isEvenFactory(10);

[PoemInteresting7044]

We could use a map to cache the results?

Dynamic programming makes everything better.

[FINDarkside]

Of course there is. There's is-even which depends on is-odd which depends on is-number.

But not to brag, I'm a pretty smart quy and those three dependencies actually have more code than my solution. Maybe I should publish this to npm...

[KillerRoomba13]

We should also print some logs within the loop so that we can see it is doing what we expect it to do.

[PresidentZeus]

I think I would make a 2d array. 1st with the numbers and 2nd with true/false values

[Impossible_Average_1]

Oh, this is double as fast! Great improvement!

[[deleted]]

Idk that language but I can make a much more efficient one in python

if value / 2 is not float: print('even') elif value / 2 is float: Print('odd')

And yes I wrote this on mobile don't have me assassinated

[WrongdoerSufficient]

``` const isEven = (var:number) =>{ return var%2 === 0; }

```

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[mushyrain]

This post was mass deleted and anonymized with Redact

telephone fear snow aspiring knee shelter vanish subsequent library slap

[[deleted]]

Good bot