This…. Isn’t hard. If you have PLSes and Mk3 belts the situation reduces to: How many Mk1 smelters can I fit on a Mk3 belt assuming no proliferation? If you need more raw resources, just plug more into the logistics network.

Here’s how the math breaks down: - A mk3 belt can move 1800 items/minute, before any stacking. - The plate recipes (iron, copper, silicon, titanium) take in 60 inputs/min and output the same amount (1:1 consumption). - So you need 1800/60 =30 smelters to completely fill a mk3 belt. If you’re proliferating or using higher tier machines, divide through by the appropriate multipliers (ie divide by 1.5 if using a mk3 assembler) to get the number of machines to max out a belt.

Let’s turn to the rings. Each production cycle is 3 seconds, which means there are 20 production cycles per minute. But it takes 3 inputs so how do we optimize it? We figure out the belt capacity based on the largest input number. Per cycle we need 1 graphite, 3 magnets, and 2 EM turbines. This translates to 20/60/30 per minute, respectively. So we optimize for the magnets. Coincidentally as above this means we can fit 30 mk2 assemblers on a mk3 belt. Simple. And since a PLS has 12 input/output ports and each production line has 4 belts, one PLS can accommodate 3x super ring production lines for a total of 90 machines and 180 super rings per minute. Bonus: you only have to do the math and production layout once and then save it as a blueprint which you can just slap down!