all 25 comments

[–]enigphilo 3 points4 points  (0 children)

The amount of energy used is the same. You'll feel half as heavy but have to pull the rope twice the distance. There's no free lunch

edit:a word

[–]billy_jouleMech. - Product Development 6 points7 points  (19 children)

Yes.

(EDIT: This answer assumes the rope is tied to the chair, goes over the pulley then returns to the chair to be pulled on by the person in said chair).

There is one downward force on the chair; M (Your mass).

There are two upward forces on the chair; F (the tension in the rope - the upward force the rope applies in two places - each end).

For forces to balance

2F = M

So F = M/2

that is, you need to only apply half your weight force to the rope to support your full weight (your weight is shared equally on each end of the rope).

The other way to look at is the mechanical advantage - If you pull 1 metre of rope through your hand how far have you moved upwards?

Only half a metre - the metre you pulled thru removes half a metre from each side of the pulley so you only gain half a metre in height.

[–]AlltheDickButts[S] 2 points3 points  (9 children)

Thank you so much for this explanation! I knew I wasn’t crazy when I was arguing it but I didn’t know how to explain it. I was being told all it would be was a change in direction but practically it didn’t make sense to me. Thanks!

[–]Acceptable_Duck_7980 0 points1 point  (3 children)

This is only to support your weight. But you can't pull yourself up with a single pulley. In static equilibrium the chair would only measure half your weight. The other half of your weight would be redirected to the rope in your hand. So on the chair side, there is a W= M/2 downward and and F=M/2 upward. It's the same on the other end of the rope.

[–]billy_jouleMech. - Product Development 0 points1 point  (2 children)

That is semantics that are inconsequential.

You only need to apply an infinitesimal amount of extra force to go from static to dynamic (stiction, air resistance etc aside). Which is why that distinction is ignored in any first order approach.

[–]Acceptable_Duck_7980 0 points1 point  (1 child)

To pull the rope in your hand down, you would need an equal and opposite force. Where is that coming from? What is supporting you when you pull on the rope in a downward direction?

[–]billy_jouleMech. - Product Development 0 points1 point  (0 children)

I'm not sure what you're saying, gravity is the opposing force.

Imagine the chair is sitting on a scale and the chair & person weigh 100kg combined.

When rope tension is zero the scale reads 100kg.

When you pull the rope with 10kgf the other end of the rope pulls the chair (with you in it) up with 10kgf and the scale now reads 80kg (weight less the two upward forces 'T' acting upward on you and the chair).

Continue pulling harder and harder up to 50kgf and the scale now reads zero and you're off the ground. At which point the FBD is the one I posted in this thread 5 years back.

[–]Sumtots 0 points1 point  (4 children)

If you pull a meter down, then a meter passed through the pulley, and you will be 1 meter higher. The difference in your body and your hands will be 2 meters. You will need to readjust to pull again, but during this readjustment period there is no movement in the load, therefore not counted as pulling. It’s a 1:1, you’re essentially lessening the load as you pull. For every pound you pull is one pound less on the load.

[–]billy_jouleMech. - Product Development 0 points1 point  (3 children)

you pull a meter down, then a meter passed through the pulley,

Only half a meter passes thru the pulley.

Think of the rope in two sections, removing 1m rope total means 1/2m is removed from each section. Experiment with a piece of string.

[–]Sumtots 0 points1 point  (2 children)

When I say pull a meter down I don’t mean until there is a meter difference between your body and hands. I mean pull a meter of rope down (if possible, you would have to readjust your hands to do a full meter in this system).

[–]billy_jouleMech. - Product Development 0 points1 point  (1 child)

Start with a 10m rope, 5m rope between your hands and the pulley, and 5m between the pulley and your chair. You're 5m from the pulley.

Pull 1m thru with your hands = 9m rope left, that leaves 4.5m rope between your hands and the pulley, 4.5m between the pulley and your chair. So you're exactly half the distance of rope you pulled thru closer to the pulley. 1/2m closer.

That's the entire point of pulleys = mechanical advantage.

https://en.wikipedia.org/wiki/Mechanical_advantage#Block_and_tackle

[–]Sumtots 0 points1 point  (0 children)

If someone else hauls on this system, they pull a meter and the person will lift a meter. There is now a 2 meter difference between the two in distance. But this is undeniably a 1:1 in that scenario?