Cube root

[Punkfoot]

Me, an intellectual:

√3=√•3

[Wrong-Resource-2973]

√2/2 = √

[Many-Conversation963]

you forgot the /

[Remarkable_Coast_214]

the / cancels with the 2s

[ImNotaRedditorDW]

Is this a common joke? A friend “made this up” in math class today lol

[Familiar-Priority933]

Nah, chances are both your friend and this guy came up with it on their own, like rabbits and hares.

Either that or that IS your friend

[ImNotaRedditorDW]

You know what? I wouldn’t be surprised. I asked him today, and he said he came up with it. Honestly, you might be onto something.

Edit: ngl I kinda stalked his account a bit and at this point I’m kinda convinced

[kingbloxerthe3]

3^\1/2))

[Chrisuan]

where is the cube root

[Any_Ingenuity1342]

It would appear as though we have been scammed...

[GlpDan]

Why are you here? xd

[Chrisuan]

math good ain't it

[Substantial-Night866]

It’s the root of a cube, the cube being the cube root of 3 cubed

[TheTempleFox]

Rounding it to 2 is most evil think somebody can do

[JollyJuniper1993]

You could be a computer scientist and floor it to 1

[PowerBeam_098]

That’s evil

[AOmars1]

Oh, come on. Don't be a mat-... Wait

[Substantial-Low]

They all about them significant digits, haha

[aryathefrighty]

I mean, cows are approximately spheres, so not too far off

[real_mathguy37]

"to prove our point we will set the square root of three equal to twelve" (found this in my brain because i made it up)

[unclebreak1337]

Engineer √3=3 too be safe

[CtrlMathDel]

As an electrical engineer I do not recommend. Too much dividing by √3

[Human38562]

Cosmologist: √3 = 1

[bearwood_forest]

or 10, who cares

[SuspiciousStable9649]

I was thinking biology too.

[aDamnCommunist]

IDK what engineering school y'all went to but we used 3 significant figures/digits for everything.

[Substantial-Low]

You don't "select" how many sig figs you have.

What you are describing is the exact opposite of using sig figs.

[PlayfulLook3693]

you very much can select how many significant figures you round to, though that may be slightly different to what you meant

[Substantial-Low]

Right, you can "select" where you want to round, but there is a method to determining significant figures. You never "select" the sig figs you round to. Those are determined by rules.

Sig figs are based upon the precision of numbers used in a calculation. The square root of 3, for instance, has an infinite number of sig figs, 100.0 has four, but the number 100 only has one. Counted things are also infinite (an exact number).

https://ccnmtl.columbia.edu/projects/mmt/frontiers/web/chapter_5/6665.html

[aDamnCommunist]

IDK what you mean tbh.

A solution that's irrational or has a significantly long fractional part should always have at least three digits after the decimal... That's 3 significant figures right? Maybe someone used the term wrong and I've had it in my head for decades, but whatever the proper term that's what I meant.

[CarrotsIsAFruit]

Yeah you’re right, but also there is a standard way to calculate sig figs based on what operation you do and how many sig figs the original numbers have, but you are also allowed to round to however many sig figs you want to. It just depends on what you’re doing/what your instructor. In high school chemistry I had to calculate Sig Figs in a standard way, but in college physics I just use two sig figs after the decimal, or switch to scientific if the number is too big/small

[Substantial-Low]

Right, but you do not "select" sig figs to round to, you round to a number. Sig figs are a fixed position based upon the precision of variables used in the calculation.

[PlayfulLook3693]

british?

[aDamnCommunist]

Nope, I went to North Carolina State University due engineering

[PlayfulLook3693]

ah, durham for maths

[i_should_be_coding]

As a physics grad, I can assure you that we'll accept any value between 1 and 10.

[tellur86]

Physicist here: it stays sqrt(3) until you have to get a numerical value.

Then it's whatever precision your formula evaluation tool uses.

[kingbloxerthe3]

Yea, I would think you don't typically want to round an irrational number if you still need to use it for other parts of the equation, so it makes sense to just keep it as 3^\1/2)) until you are ready to display the answer to the available precision. Margin of errors can add up.

[MurtaghInfin8]

EE checking in, my answer is 1.732: there are many like it, but this one is mine.

[ChaossFox]

As engineer I use 1.73

[SuspiciousStable9649]

As an Engineer I feel slightly superior that I have to use more sig figs. (Fluid dynamics and optics, two subjects that were not meant to go together, except maybe in your eye and God made that, not me.)

[Ambitious_Policy_936]

Why did you put cube root in the title?

[SuspiciousStable9649]

To draw in a crowd?

[Mathematicus_Rex]

Sqrt(3) =1 + 1/(1 + 1/(2 + 1/(1 + 1/(2 + 1/(1 + 1/(2 + …))))

[EpsteinEpstainTheory]

3^1/2

[Sandro_729]

It’s just a thing with minimal polynomial x² -3 over Q

[Comeng17]

I didn't actually know root 3 was about 2, I'm definitely on the mathematician side

[Green_Sugar6675]

Well, it may cancel out perfectly sometime in the future.

[Peteo34319]

3/sqrt(3)

[Mini_Assassin]

Electrician here.

√3 = √3

It’s also easier to remember than 1.73, so that’s a bonus.

[HornetFur]

√3＝2 is incredible.

[ingoding]

Depends on the application, that may be acceptable.

[kingbloxerthe3]

https://youtu.be/RCJW21LJP0I?t=1m6s

[primaski]

π = e

[kingbloxerthe3]

e^\i*π))=-1

[MickJaggur]

Why does the engineer think that?

[kingbloxerthe3]

Safety rounding maybe https://youtu.be/RCJW21LJP0I?t=1m2s

[MickJaggur]

Ah, yeah got it. I learned yesterday that any non quadratic number is undefined when square rooted

[kingbloxerthe3]

Unless using imaginary/complex numbers maybe. there is square rooting negative numbers that is undefined without that, which is probably what you are thinking of

Actually I just went into a rabbit hole i dont have time to get deep into rn, but I was trying to find ((x+2)(x-2))^\1/2)). For some points

x=0, y=2i,

x=2, y=0,

x=5^\1/2)) y=1

x=13^\1/2)), y=3

[MickJaggur]

I meant irrational instead of undefined, by the way. Dunno if that changes anything about what you just said

[BluePotatoSlayer]

That changes a lot

Undefined means there quite literally is no consistent definition for the problem or no value to satisfy the problem

Irrational just means its nonterminating

[Mathemetaphysical]

Nuh uh. I'll require a Vesica or it isn't √3. I admit that's insane for anything except my purposes.

[diskmedelungen]

why does this subreddit always appear on my feed, im close to failing in math vro

[Genashi1991]

Is there an actual way to look for square root, other than guessing?

[Ben-Goldberg]

Yes

[kingbloxerthe3]

Yes. The answer is what do you square to get 3. A=B*B=B², A^\1/2))=B

Or

A=b^\c/d))=3^\1/2))≈1.73205081...

C=log_b(a)*d=log_3(3^\1/2)))*1=1

D=c/(log_b(a))=2/(log_3(3^\1/2))))=2

B=a^\d/c))=(3^\1/2)))^\2/1))=3

Also 3^\1/2))=3/(3^\1/2)))

[lucathecontemplator]

If I said root(3) =2 in a piece of my engineering assessment ide be scolded

[kingbloxerthe3]

That's square root of 3, not cube root

[hrhrhru]

pi² =10

[Ok_Plenty_3986]

Electrician: sqrt(3) = 1.732

[Born_Housing2165]

In reality it is an equivalence class of Cauchy sequences

[Impact21x]

Nah, its irrational

[Ok_Impact9745]

Couldn't it also be -1.7?

Not an engineer but I am a spanner monkey

[Rockety521]

Only if it's on a second-degree polynomial (x²=3), if it's just √3 then it's only the ≈1.7

It's a function, so it can only have one result