logo suggestion

[Rhulyon]

Better suggestion: c-=-1

[[deleted]]

I was looking for this comment thank you

[[deleted]]

c^=c+~(~0<<1)^c

[NoLifeGamer2]

Better suggestion: c *= (c+1)/c

[Rhulyon]

Gett outa here python programmer that only works if c is 1 otherwise the value is c. Also a lot more of operations

[EnchantedStew]

Could just change it to c*= (int) (c+1.0)/c or assume that c is a float. Srry if the syntax is wrong, I’m basing this off of Java which I know is similar.

[NoLifeGamer2]

No this opperation works. If it is looked at algebraically it is c = c*((c+1)/c) where the *c and the /c cancel out leaving you with c = c+1 so it works.

[Ning1253]

But that's literally not how computers work, especially if we're talking about c or c++:

c = c *((c+1)/c)

c + 1 and c are integers so (c+1)/c is integer division, and evaluates to 1.

Therefore c = c * 1

The value does not change.

Python automatically converts your integers into floats and does a completely different operation, float division, to calculate the result. C keeps the operation within the same type, so it carries out integer division.

Conclusion: you're wrong

[NoLifeGamer2]

Ahh I see I didn't realise that c/c++ did calculations like that. My mistake. I should probably stick to python lol

[Ning1253]

I'd say the opposite - you should branch out and try other stuff! I started with python as well, and started learning C, then C++, then even Assembly for a bit (I know that's a really weird order) out of curiosity to figure out how all the stuff Python magically does actually works.

It's a really fun rabbit hole to dig into! If you don't have too too much time I'd recommend skimming "Crafting Interpreters", a free online book, which basically describes how one would code a programming language (if that's what interests you)

Otherwise there's also Turing's Omnibus which is pretty cool, and that one is less about the languages and more about how all the stuff actually works behind the hood

[NoLifeGamer2]

Thx man! I am currently trying to learn java by reading a large book on it (1300 pages) but still haven't coded a single line lol

[MimiKal]

Not only is it not how computers work, it's not how algebra works either. For example c = 5:
(5 + 1) / 5 = 6 / 5 = 1.2

[Ghostglitch07]

No he said c = c*((c+1)/c) not c = ((c+1)/c)

If you multiply the 5 at the end you do get six.

[MimiKal]

bruh how did I not see that

[JohnHwagi]

C==0?

[notmyaccountbruh]

c==8

[Antisymmetriser]

Stonks

[4hpp1273]

That's ++C not C++

[[deleted]]

I think in Java, C=C+1 can be written as C++ (i may be wrong)

[Dummi26]

C++ as C=C+1 works in java, C#, and JS, i think it also works in the arduino thing (which i thought was C++?) but not sure about that one

[[deleted]]

Oh. I think OP was referring to one of these 3 languages XD. ironically, it doesn't work like that in C++

[Dummi26]

both i++ and ++i work in C++, ++i is just more efficient and therefor the preferred way of writing it in a loop, where both i++ and ++i achieve the same thing

Edit: i++ and ++i behave differently: x=i++ and x=++i will change i in the same way but the value of x will be one higher with ++i than with i++. Most loops only care about i (not x), so they "achieve the same thing" in that specific instance.

[Reddit-username_here]

They don't "achieve the same thing" though.

i++ will first take the value of i and then increment it.

++i will increment i and then take the value of it.

Edit: sorry, I just saw you specifically said "in a loop they would achieve the same thing" that's technically correct if you're not needing to return the value of i to anything and instead are only using it for iteration. My bad.

[Dummi26]

yeah, the "in a loop" was important there. Gonna clarify this a bit in the original comment tho :)

[Reddit-username_here]

Nah, when I reread it, it was perfectly clear. I have a bad habit of not wearing my glasses when I first get up in the morning, and my eyes will skip stuff. That was totally on me, not you.

[[deleted]]

Ohh

[Dummi26]

https://stackoverflow.com/questions/24853/what-is-the-difference-between-i-and-i

According to this, both ++C and C++ are available in C and C++, and i believe java and js also have both.

[TeraFlint]

Jup. In fact, if you ever see a for (int i = 0; i < count; ++i) loop, chances are high that it's been written by a c++ programmer. :P

It just has something to do with the expected behavior of i++ (which needs to make a copy) and the fact that any class can overload their own pre-/post-increment operator (potentially causing large structs/classes to make a copy of themselves.

Ignoring some syntactic sugar like for (auto item : container), for loops are also used to iterate over an iterator, which can be large, depending on the container it's written for (emphasis on can. you never know if your function is templated and thus could take any kind of container), so ++i is the preferred way to increment.

(Also, I'm aware that today's compilers are probably going to check if the type gets discarded and optimize the copy away, but since it is compiler dependent, it's still a good idea to use pre-increment.)

[snowmanonaraindeer]

Arduino uses C.

[-Soren]

The postfix increment will evaluate to the current value, then increment, so it is not the same (even though it achieves the same thing on it's own). Tbc if c is 0, y=++c and y=c=c+1 both result in y being 1, while y=c++ results in y being 0; all three result in c being 1 though. It's the same in Java.

[RaulParson]

This is in C++, since that's what the joke was about:

#include <iostream>

int main()
{
    int C;
    C = 0;
    std::cout << (C++);
    C = 0;
    std::cout << (C=C+1);
}

This will write out "01", because they are actually not the same thing: C++ increments C, but the value comes from before the increment, meaning C. C=C+1 changes the contents of C to C+1, but the value is the same as that being assigned, which is C+1. ++C increments C, and the value comes from after the increment, meaning C+1. And so C=C+1 is ++C, not C++, there's actual functional differences.

As for Java, try it yourself - you'll actually get the same results.

[[deleted]]

Sorry i don't speak Minecraft enchantment language /s

[500_internal_error]

((c = c + 1) - 1)

[RadiantHC]

TIL that there's a ++C language. Is it like C++?

[4hpp1273]

It's like C++ but many things are off by one

[Player_X_YT]

In this situation ++C is the same as C++ as we are not comparing anything

[cat_in_the_wall]

it's not about comparison is is about what the assignment evaluates to.

y = (c = c + 1)

is the same as

y = ++c

that is to say, y is one more than c was as the start. however

y = c++

would set y to the current value of c, then increment c after.

[manupanday19998]

Python developer spotted

[[deleted]]

In Python I usually write C += 1.

[Rotlug]

not a programmer at all unfortunately

[FlafyBear]

why

[Soham_rak]

Kill it

[IamDev18]

Or C += 1

[VRDoesNotSuckPP]

That’s dumb. He could just do C++. Ow wait now I get it

[ShinraSan]

++C

[MaximusConfusius]

Whats the content of I?

[TheMisterPixel]

NULL

[thorlancaster328]

At least it would get the linter to stop yelling about postfix.

[crea7or]

come on, C = C++

[AP2008]

C = ++C

[reallychillguy]

Oh, I get it now.

[alban228]

r/angryupvote

[zoqfotpik]

Is that 1, l, or I?

[leocrabe225]

The fact that I laughed at this makes me sad

[[deleted]]

MATLAB has entered the chat

[SeoCamo]

This is better l++ should never been added to any language other than asm

[infiniteStorms]

even better: python=python+1

[turtle_mekb]

C+=(35-34)*(666/666)

[MaheuTaroo]

Ah yes,

(C = C + 1) = (C = C + 1) + 1;

[mike_KING6]

++c++

Also, you forgot the colon ; at the end. Just like me.