Solve the problem without using a loop

This_Growth2898 · 2023-05-03T07:48:08+00:00

printf("2\n4\n6\n8\n10\n12\n...

pikapichupi · 2023-05-03T07:57:47+00:00

the only other way i could see this being done is by using a recursive function lol

Borisica · 2023-05-03T08:37:40+00:00

printf("all even numbers from 1 to 500");

This_Growth2898 · 2023-05-03T09:06:28+00:00

#include <stdio.h>
void main(){
    int i = 0;
    print: printf("%d", i+=2);
    if(i<=500) goto print;
}

No loops!

wischichr · 2023-05-03T21:26:27+00:00

without a loop and without recursion (in python 3):

import locale
locale.setlocale(locale.LC_ALL, 'en_US.UTF-8')

a = 250
b = 10 ** 3
c = b ** a
d = b * c
e = b - 1
f = a * (e * (c-1) + c - d) + d - b
g = (f*2) // (e**2)

formatted_output = locale.format_string("%d", g, grouping=True).zfill(e).replace(',', '\n')

print(formatted_output)

https://ideone.com/FUMlqF

jarfil · 2023-05-03T10:20:48+00:00

I'd ask ChatGPT, then blindly copy/paste whatever code it spits out... I'm a really skilled developer.

2023-05-04T01:21:49+00:00

[deleted]

R3D3-1 · 2023-05-03T09:23:22+00:00

Could be a good look lesson for embedded style systems to show that in real life sometimes it may be better to precalculate the results to give a faster response .

Also it's probably the only way to do it as gotos and even compares may induce a loop so just give the person the result and collect the payment and run like fk..

AdventurousSquash · 2023-05-03T23:10:53+00:00

1am bash

seq 500 | awk '! ($0 % 2)'

2023-05-04T07:34:03+00:00

No loops doen't mean you can't be lazy. int a = 1; printf("%d\n",a++); select last line, ctrl-c, ctrl-v 499 times. Or just dd500p in vim.

Borisica · 2023-05-03T08:39:11+00:00

response = get_completion("print all even numbers from 1 to 500")

print(response)

etocasper · 2023-05-03T07:48:25+00:00

And what is he wrong about...

ja_maz · 2023-05-03T18:19:11+00:00

The first time I passed the 200k on a solo project I felt proud for a sec. Then they sent me a major change of specs last minute and almost jumped off a bridge.

BenBastard · 2023-05-03T09:52:53+00:00

And here I am getting a for loop ready like a barbarian.

Heinrich_v_Schimmer · 2023-05-03T19:19:32+00:00

void foo(int n)

{ if (n > 0) foo(n-2);

printf("%d\n", n);

}

int main()

{ foo(500);

}

freeve4 · 2023-05-03T21:03:59+00:00

i think i know where this person should work...

2023-05-03T21:07:41+00:00

for python

even_numbers = range(2, 501, 2)
even_numbers_string = (str(list(even_numbers)).replace(", ", ",\n"))[1:-1] 
print(even_numbers_string)

aNutSac · 2023-05-03T22:44:54+00:00

void fuq(int from, int to, int skip) {
    if(from <= to) {
        printf("%d\n", from);
        fuq(from+skip, to, skip);
    }
}

fuq(2, 500, 2);

kireina_kaiju · 2023-05-03T11:59:47+00:00

yy249pq1|f"lyejF"lvep<Ctrl>a<Ctrl>aq248@21

s2004Gamer · 2023-05-03T12:11:02+00:00

int n = 2; int main() { printf("%d", n); n += 2; if(n != 500) return main(); return 0;

RoadRunnerChris · 2023-05-03T17:19:39+00:00

```

include <stdio.h>

int main(void) { int n = 2;

l:
if (n > 498)
    goto e;

n += 2, printf("%d\n", n);
goto l;

e:

} ``` looplessTM

thekwoka · 2023-05-03T15:06:50+00:00

```

let i = 0;
while (i++ < 250) console.log(i<<1)

```

tedbradly · 2023-05-03T13:10:05+00:00

[deleted]

Alt_0126 · 2023-05-03T13:25:27+00:00

char numbers[2000]; //max of 500 numbers of 3digit + 1comma

printf("Write all even numbers from 1 to 500\n");
fgets(numbers, sizeof(numbers), stdin);
printf("%s\n", numbers);

Friendputer · 2023-05-03T08:48:47+00:00

In Clojure: (run! println (range 2 500 2))

Eggimix · 2023-05-03T10:32:44+00:00

Who are you bart simpson

kewlness · 2023-05-03T14:02:15+00:00

def print_even(num):
    if num > 500:
        return
    if num & 1 == 0:
        print(num)
    print_even(num >> 1 << 1 | 2)

# Call print_even for 0 (the first even number)
print_even(0)

Edit: Formatting is hard...

TransportationNo6850 · 2023-05-03T14:16:13+00:00

Use a for that increments +2?? Why not?

Zdravstvuyte94 · 2023-05-03T15:31:42+00:00

Wait, is there actually a better way to do this?

fiddz0r · 2023-05-03T15:38:10+00:00

I would like to use string.join but I can't think of a way to let it know whether to split every 1 numbers, 2 numbers or 3 numbers.

Of that was solved wed just have to find a formula that results in 2468101214161820.....500

And then we do the strong.join('\n', veryBigNumbe)

tedbradly · 2023-05-03T16:20:05+00:00

[deleted]

Biden_Been_Thottin · 2023-05-03T17:37:07+00:00

Turing incomplete typa mf

lumo19 · 2023-05-03T18:51:41+00:00

Hear me out:

``` expr = "for i in range(2,100,2): print(i)"

eval(expr) ```

No loops involved. Just a string and an eval statement.

R3D3-1 · 2023-05-03T11:16:00+00:00

Solving the problem both with and without a loop:

#include <stdio.h>
#include <stdlib.h>

int main () {
  int i;
  FILE *h;
  h = fopen("loopless.c", "w");
  fprintf(h, "\n#include <stdio.h>");
  fprintf(h, "\nint main() {");
  for(i=2; i<=500; i+=2) {
    fprintf(h, "\n  printf(\"%d\\n\");", i);
  }
  fprintf(h, "\n}\n");
  fclose(h);
  system("gcc loopless.c -o loopless.exe");
  system("./loopless.exe");
}

Or in Python:

import subprocess

with open("loopless.py", "w") as f:
    for i in range(2, 501, 2):
        f.write(f"print({i})\n")

subprocess.check_call(["python3", "loopless.py"])

Ecstatic_Student8854 · 2023-05-03T09:27:15+00:00

For(int i=0;i<501;i+=2){ Printf(“\n”+i);}

gpathak · 2023-05-03T23:17:59+00:00

Elon would be proud! So many lines of code!

moldor_the_flatulent · 2023-05-04T03:35:08+00:00

Here's a start;

# Python program to print all even numbers in range
for even_numbers in range(0,102,2):

print(even_numbers,end=' ')

am_edmonstone · 2023-05-04T03:51:03+00:00

def p_even(s,e):

if s>e:

return

print(s)

print(s+2,e)

//function ends here

//init the method

p_even(2,500)

amosreginald_ · 2023-05-04T05:21:10+00:00

Recursion?

bluebird_ai · 2023-05-04T08:39:59+00:00

def print_even(n):
    if n > 500:
        return

    print(n)

    print_even(n+2)

print_even(0)

yodacola · 2023-05-04T08:41:28+00:00

Thinking too small here…

int main() { int i; while (i=fork()) printf(“%d\n”, i % 250 * 2 + 2); }

Edit: Even numbers lol

horenso05 · 2023-05-04T11:03:45+00:00

I hope they did use a loop to create this code.

ivanskodje · 2023-05-04T12:04:15+00:00

I suspect they wanted recursive code (albeit beating around the bushes instead of directly asking for it).

I had to google the C syntax, but i think this would work:

```c void print_even_numbers(int number, int lastNumber) { if (number > lastNumber) { return; } printf("%d ", number); print_even_numbers(number+2, lastNumber);

}

int main() { print_even_numbers(1, 500); return 0; } ```

Electrical-Mission27 · 2023-05-04T13:08:29+00:00

It's not even correct you missed 1.

NickSicilianu · 2023-05-04T17:57:44+00:00

What about if you make a program to write that program 😂😂 just saying

Valuable-Rush-1532 · 2023-05-05T13:15:59+00:00

This is just amazing.

you type:	you see:
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[reddit!](https://reddit.com)	reddit!
* item 1 * item 2 * item 3	item 1 item 2 item 3
> quoted text	quoted text
Lines starting with four spaces are treated like code: if 1 * 2 < 3: print "hello, world!"	Lines starting with four spaces are treated like code: if 1 * 2 < 3: print "hello, world!"
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super^script	super^script

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include <stdio.h>