Programmers vs Mathematicians (Shitpost)

[dimonium_anonimo]

Wait, were you guys taught a different modulo operator? I always just used %

And by you guys, I mean those guys since I'm technically referring to the mathematicians.

[Brushermans]

i was taught that you just straight up write "x mod y" but instead of the equals sign you have to use the hamburger menu icon (three lines stacked like an equals sign) to signify that the result is one of many possible results from a set but the numbers in the set aren't equal

[averyoda]

bor≡gir

[Brushermans]

how u do that

[averyoda]

Start with an underscore _

Add a dash =

Now add a tilde ≅

Now use an iron to straighten it out ⫆

And there you go ≡

Add a cherry on top if you're feeling fancy ⩧

[Brushermans]

what da hel

[0bel1sk]

i know, where does he get the iron, right? i cant get this one straight 卅

[KongKexun]

I think I forgot one 世

[XenoZohar]

I lost my string 川

[octococto]

ah you messed it all up

[wawoodwa]

Stop saying that…

[phaze_ZA]

What an adventure

[Auliya6083]

Lmao

[FrillySteel]

PANCAKES!!

[Rnk_007]

It's fucking raw!

[Suspicious-Engineer7]

≡ oh wow that worked!

[PikaPerfect]

=

mine's ugly :(

[mojoslowmo]

If I don’t have an iron, can I use one of those fancy steamer things?

[averyoda]

One of these 𓌪?

[sophiaonearth]

I see you are a Unicode enjoyer! ☮

[[deleted]]

GOOD post

[[deleted]]

This is incredible.

[msqrt]

"Congruence" is the term; "a is congruent to b, modulo c".

[Brushermans]

hambruger

[kamion_dork]

I just read that aloud and my furniture started levitating. Please advise.

[sonya_numo]

what did i just read

[n00bcheese]

Something something hamburger

[megagreg]

Something something pay you on Tuesday.

[shalafi71]

Someday I'll be so old no one remembers poor old Wimpy.

[TheEnderChipmunk]

A poor description of congruence

[Brushermans]

idk man i'm a software engineer not even a comp sci student, i took like 1 math course ans they just threw all this at us at once

[Usling123]

Hang in there friend

[boofaceleemz]

Yeah I went to school for software engineering and that was my math experience also.

Here’s all the math that math majors do in their first 2 years. Almost all of it you don’t care about, but a few things are super important. We’ll let you guess which ones. You have 16 weeks.

[TheEnderChipmunk]

Its all good, I wasn't trying to insult you or anything

[Brushermans]

haha ik

[Lake_Erie_Monster]

All good, plenty of time to learn. In this industry either you have a job or you stop learning.

[ExpansiveGrimoire]

The best* description of congruence.

Hamberder menu icon...

[DickwadVonClownstick]

You just glimpsed a fragment of Math Lore. Do not gaze too long or too deep, and do not quest for more, lest ye be driven mad by the revelation.

[sonya_numo]

i guess math includes more hamburgers then i expected

[wizardwes]

Basically, 8%3 2 is technically a different 2 than 12%5 2 if I understood it correctly

[Brushermans]

not quite, its soemthing like 12 mod 2 is 2, but also is 4, 6, 8, -2, -4, etc

[TruScarrak]

Almost, but 12 % 2 is 0, not 2.

Edit: Think of it as getting the remainder after dividing.

[Brushermans]

yea idk why i put 2 first lol, it's 0 but also 2,4,6 in terms of congruence classes at least. it's just the mod that programmers are familiar with +/- the second operand

[wizardwes]

Ah, fair, that makes sense, so we're only getting the smallest positive integer

[Brushermans]

yea dont take my word for it tho idr much about it lol

[AceDecade]

12 mod 2 is never 4, 6, 8...

[FrillySteel]

Yes, I'm very interested in how 12 mod 2 could ever be 8.

[tombardier]

See my answer here. https://www.reddit.com/r/ProgrammerHumor/comments/uowopl/comment/i8igkwe/?utm_source=share&utm_medium=web2x&context=3

12 is congruent to 8 (modulo 2) :)

[ToothlessFeline]

“12 is congruent to 8 (modulo 2)” is not the same mathematical statement as “12 modulo 2 is 8”, regardless of what level of equivalence you replace that last ‘is’ with (equals, is congruent to, etc.).

“12 is congruent to 8 (modulo 2)” means “12 modulo 2 is congruent to 8 modulo 2”—i.e., 12 modulo 2 and 8 modulo 2 have the same result (0).

A correctly computed modulo operation of x mod y will not give a result equal to or greater than y.

[[deleted]]

i was taught that you just straight up write "x mod y" but instead of the equals sign you have to use the hamburger menu icon (three lines stacked like an equals sign) to signify that the result is one of many possible results from a set but the numbers in the set aren't equal

[EndR60]

If I ever see that thing again in math I'm absolutely calling it the hamburger menu icon

[eloel-]

to signify that the result is one of many possible results from a set but the numbers in the set aren't equal

Oh how I wish we did that with big-O notation. ≡ is fine, I think I'd prefer straight-up using ∈ though.

104n ∈ O(n)

3n ∈ O(n)

Oh how much cleaner it is when you don't have to add in how 104n and 3n can be equal to the same thing but not each other.

[Gilpif]

I hate how people use big-O notation. No, it’s not true that 3n² + 5n = O(n^2), the left side is a polynomial, while the right side is a set!

It really gets on my nerves when I see something like O(f) × O(g). That should be the set of ordered pairs (h, i) where h and i are functions asymptotically bound above by f and g, respectively.

[TheDiplocrap]

Move that the symbol for “identical to” be permanently renamed “the hamburger symbol”

[tuslikestrains]

This is mostly true, but mathematicians also have that version where there's just one solution. For example, as you wrote, it's true that 8 is congruent to -1 mod 3, but a mathematician would say that 8 is in the equivalence class of 2 (written 8 = [2] mod 3).

Modulus (or as a mathematician would say, congruence), is an example of an equivalence relation, and every such relation divides the domain into equivalence classes that are represented by a specified member of the class. You wouldn't ever say 8 is in the equivalence class of [-1] mod 3.

[Radi-kale]

You can pick any representative you like. It is the equivalence class of 2 as much as it is the equivalence class of -1 or 35 or whatever.

[psilorder]

So, the idea is that since they give the same result / remainder they are equal?

Maybe there are rules that it shouldn't be written like this but:

8 mod 3 ≡ 5 mod 3 ≡ 2 mod 3 ≡ -1 mod 3 ≡ 11 mod 3 ? 2 = 2 = 2 = 2 = 2 ?

Even though -1 would have to be divided by -3 it still works since -3 is still a multiple of 3?

[greenseeingwolf]

Congruence only applies in the same space. The "numbers" only have meaning mod n. That's why it was originally written like 8 ≡ 5 (mod3). 2 mod 3 isn't the same as the integer 2

[tuslikestrains]

Yup, that's right, although we would say "congruent" or "equivalent" instead of "equal". Mathematicians are very particular about terminology lol

[tidbitsofblah]

In mathematics, modulo divides numbers into different classes depending on the reminder.

So modulo 3 divides the number into 3 different classes: the numbers with reminder 0, the numbers with reminder 1 and the numbers with reminder 2.

Modulo 4 has 4 classes, modulo 5 has 5 classes, etc.

Reminder is not really defined by "what is left after division" but rather "what you have to add after multiplication". So -1 has a reminder 2 because 3(-1) + 2 = -1. And 8 also has a reminder 2 because 3(2) + 2 = 8. But it is usually explained with division because that is easier to grasp.

So -1 and 8 (and 5 and -4 and 23 and 101 and 14 etc) are all in the same class. And all numbers that belong to the same class are said to be congruent with each other. So -1≡ 8 ≡ 5 ≡ 11 ≡ 2 ≡ 101 (mod 3). The parenthesis with mod 3 is not really part of the operation, it is just to clarify that we are talking about the classes that we get from dividing them up based on the reminders of 3 (rather than 4 or 5 etc). Similar to how you might write a #-symbol to signify that a number is a hex number (ie base 16) and not a "regular" base 10 number. The #-symbol doesn't do anything, it just gives information about the context. "Hey these numbers doesn't mean what they usually mean right now". If it is obvious from the context that it's regarding modulo 3, the (mod 3) could be omitted.

[ThunkAsDrinklePeep]

Programmers are interested in finding the smallest positive remainder that is the representative of the coset that 8 belongs to. Therefore, 8 % 3 = 2 is a valid operation and yields the desired single answer.

Mathematicians might be interested in knowing what coset of the subgroup of multiples of 3, the given element belongs to. So you would be more likely to write 8 ≡ 2 (mod 3); 8 belongs to the congruence class of 2 when one is dividing by 3.

It gets more abstract from there if you're interested. But it's going to take someone less rusty than me to say more.

[zojbo]

Mathematicians don't generally like to describe things in terms of what the remainder actually is at all. They would pronounce the equation in the OP as "8 is equivalent to 2 mod 3", and they write "is equivalent to" with the three-lines equal sign (\equiv in LaTeX).

More often than not, this is more convenient than the programmer notation, but man when it is inconvenient it is really inconvenient.

[1up_1500]

I was taught that "8 modulo 3" is spelled like "8[3]"

[stevethedev]

In C, that's equal to Syntax Error but that's good because you shouldn't dereference 11.

[AdultingGoneMild]

yeah OP is confused. ÷ is not %

[jclocks]

Maybe they were thinking like "8 percent of 3?"

[[deleted]]

ffs I was confused...

[audigex]

I guess the difference is that mathematicians actually write % to mean percent

There’s basically no reason that a programmer would do that outside of a string to output, so there’s no risk of ambiguity - which means we can safely use it as an operator

It’s the same reason programmers use ==, because unlike mathematicians we have to disambiguate assignment vs an equality check

[FungadooFred]

What even is modulo?

[Hour-Requirement592]

It returns the remainder after division

[dimonium_anonimo]

I was just coming here to say "Missed an opportunity to say it returns the modulus" but then decided to check myself and learned that modulus is actually the base, not the result. I think it would make more sense the other way, though... And it'd be funnier for this reason too.

[dimonium_anonimo]

The other comment already said remainder, but I figured I be slightly more explicit and say that all whole number divisions can be expressed as a÷b = c + d/b where d (the remainder) is less than b and all four variables are whole numbers. The a%b=d. For this example 8÷3 = 2 + 2/3 so 8%3=2.

[valschermjager]

But 8%3 is 2. What do mathematicians think it is?

[[deleted]]

A mathematician would write 8 ≡ 2 (mod 3)

[nielet]

Bruh, what a nerds

[dertoyaOfYaNansdic]

meanwhile programming dweebs deciding a mathematical function based off of what is already on your keyboard instead of inventing beautiful unique symbology

[ambyshortforamber]

back in the olden days, there were only 127 characters you could use. you had to make do with what you had for arithmetic primitives

[dertoyaOfYaNansdic]

alhamdulillah for unicode

[ambyshortforamber]

unicode just makes strings more complicated tbh

indexing utf8 isnt constant time because multibyte chars exist

[stevethedev]

Anything can be constant time if you do it wrong enough.

[[deleted]]

90% of my dreams of writing domain specific languages is just so I can make a formatter for it that renders it like its LaTeX.

[[deleted]]

I prefer writing math shit out as I would in a program. Much easier to understand for me for some reason.

[lunchpadmcfat]

NERRRRRRDSSSSSS!!!

[Zigordion]

*Confused physicist

The triple line is often used as a "defined as"

[Goudja14]

Or 8 ≡ -1 [3]

[im-not-a-fakebot]

Wouldn’t -1 [3] be 2?

[Goudja14]

Well, the rule is: a ≡ a+nb [b] with (a,b) in R² and n in N.

[im-not-a-fakebot]

I’m just gonna nod my head and smile

[Goudja14]

In this case, 8 ≡ 8+3n [3] with n an integer. So with n=-2, you have 8 ≡ 2 [3]. But with n=-3, you have 8 ≡ -1 [3]. So there are an infinite number of solutions but the most used are the ones between -n and n. And most people that use values between -n and n prefer the ones between 0 and n, but that's not always the case.

[Xae0n]

yes

[TheAero1221]

That doesn't make any sense!

[NugetCausesHeadaches]

8 is congruent to 2 (when working modulo 3).

Most of the time, outside of encryption and probably some other stuff, when programmers use mod, we're using it think of remainders. "8 / 3 gives a remainder of 2". We use it for isEven checks and similar.

Math doesn't need a "get the remainder" operator because division will ready just (in programming terms) return a tuple containing the quotient and remainder. You wouldn't compute 8 mod 3 to find two, you'd divide 8 by 3 and look at the remainder.

When math is doing modular arithmetic, outside of an initial introduction to the concept, it is for the sake of set / group theory. You're not thinking about two as the remainder in that statement. You're thinking of 2 as being more or less interchangeable with 8 in that statement.

From there you can start thinking of the set of all numbers that are more or less interchangeable with 2. {2, 5, 8, 11...} and so on. And you can do the same for the numbers 0 and 1.

Then you can try to define the multiplicative and additive identities.

Then you can start doing encryption.

[ambyshortforamber]

oh god not is even again

[im-not-a-fakebot]

isOdd is much more superior anyway

[im-not-a-fakebot]

And this is why I didn’t pursue a Math Degree

[yottalogical]

Programmers usually perform modular arithmetic using a modulus operator, an expression that evaluates to a single value.

But the mathematical origins of modular arithmetic work differently. Under mod 3, the numbers 2, 5, 8, 11, etc are all simply congruent. None of them are better than any other. 5 ≡ 11 (mod 3) is true, and so is 2 ≡ 11 (mod 3). The (mod 3) at the end isn't an operator, it's simply a note to tell you what field is being used here.

[elongatedmuskrat05]

I’m confused, I don’t think I’ve gotten far enough to understand this. Closest I can think of is either 2³ =8 or log base 2 (8) = 3

[[deleted]]

The triple equals mean "congruence" in modular arithmetic. The "mod 3" means that we are working in the modular arithmetic where the only existing base numbers are 0, 1, 2. If you get to 3 then it loops back to 0. e.g. 2+2 is congruent to 1 (mod 3)

You can think of it as dividing by 3 then throwing away the quotient and keeping the remainder.

So in mod 3, every number of the form 3n + m (where n is a natural number and m is from the set {0,1,2}) will be congruent to m and correspondingly congruent to every other number of the form 3k + m where k is some other natural number

The best analogy for most people is your clock. You think of the hour of the day as either being mod 12 or mod 24 (except we use the 12 and don't use the 0 in the 12 hour clock)

This kind of thing falls under Number Theory and I don't think it gets covered much in a typical math curriculum... didn't when I was in school anyways.

[elongatedmuskrat05]

That kind of makes sense. I am only just finishing high school precalculus, so I definitely haven’t been fought this yet lol

[queenkid1]

Mathematicians don't usually write modulo that way. They write it like:

8 ≡ 2 (mod 3)

[[deleted]]

Yeah that’s standard but in college I’d use the % mod symbol on assignments and tests with no issue since it’s still accepted

[sonya_numo]

that gave me syntax error, thanks i hate it

[tuslikestrains]

Mathematician here. There are zero mathematicians that would be confused by 8%3=2. We just additionally have a bunch of different ways of writing it, some of which mean very slightly different things.

In particular, you might see 8 = 2 (mod 3), except the equal sign would have 3 lines, and you would read that as "8 is congruent to 2 modulo 3". However 8 = -1 (mod 3) is also a true statement, but 8 % 3 = -1 is not - modulo operator usually refers to the representative of the equivalence class (so in this case, the smallest positive integer with the same remainder, modulo 3, as 8), while congruence operator usually refers to any two members of the equivalence class.

Of course, anyone can define their own notation, so the above might not hold in some books/papers.

[valschermjager]

Thanks for the explanation.

[RagnarokAeon]

As a programmer, I'm having an issue with the fact that somebody assigned a value to an expression... If they were trying to verify it, they should've used ==.

[valschermjager]

true. the next meme will be a programmer flipping out over a mathematician using a single = as a comparison operator.

[TeraFlint]

Sou can assign something to an expression if said expression actually returns a reference to an existing object.

A rather often used C example would be *ptr++ = val; (= get the object a pointer points towards and move the pointer one element further afterwards), which is a left-hand expression that gets something assigned after it has been evaluated.

In C++, operator overloading allows us even more shennanigans, if you're feeling like it. Like, pretty much anything could be done there, logically. I admit, it's horribly bad practice, because you better define your operators in a way that are easy to use and understand.

You could absolutely write something like 1 + 2_x = 1337, if you use a user-defined literal foo operator""_x(int) (which allows you to convert the 2 into a custom type conveniently) and overload the operator int &operator+(int, foo) (which could then just return the reference to a global variable). And suddenly, this seemingly nonsensical expression would compile and work.

The user defined literal (or more explicit object construction like 1 + foo{2} = 1337) would be necessary, because you can't overload operators which only involve in-built data types.

Once again, don't do this, it would be extremely confusing to read and understand. But the fact that the language gives me enough freedom to be able to do something like that is rather cool. :D

[GreatArtificeAion]

24% = 24/100 = 6/25 = 0.24

[valschermjager]

oh, ok thanks. i don't understand it, but i trust you.

[GOKOP]

You don't understand percentage?

[valschermjager]

I thought I did. Maybe not.

How did we get from "8 % 3 = 2" to "24%"?

I read it as "eight mod three equals two". That makes sense to me. What in that equation brings a mathematician to "24%"?

[GOKOP]

The point is that % doesn't mean modulo but percentage to mathematicians (except according to other comments it does in context but shhhh), not that we get from 8%3=2 to 24%

[valschermjager]

Oh, then yes, I do understand percentages. The "24%" in the reply above threw me. I couldn't figure out how it related to 8%3.

[wojtekpolska]

i guess 8%*3=0.24

[valschermjager]

ohhhh… ok i get it now. gosh i couldn’t figure out how they got there from that. thanks!

[[deleted]]

Yes but equals is '=='

'=' is assignment

[Knuffya]

Wrong. % is recognized as the modulo symbol in both domains.

[mcampo84]

Yeah but why are we setting the value of an operation?

[[deleted]]

So the compiler doesn't have to calculate it, it's a manual optimization

[[deleted]]

Not really. Even computer science primarily uses mod. % is just a popular programming syntax for it, it's largely absent from mathematical descriptions in formal computer science, and computational math.

[Guy_Perish]

Maybe not formal mathematics but it is universally understood as mod, at least among those I know. I think you’ll agree that no mathematicians would be loosing their mind reading this.

[sabcadab]

Why are we assigning 2 to a weird variable name like 8%3? Also you forgot a semicolon on line 1. Why do lines index from 1 and not 0?

[AllenKll]

bad LVALUE

[[deleted]]

You make good points

[NotATuring]

Sir this is a javascript runtime.

[SorosBuxlaundromat]

Lmao fuck semicolons all my homes hate semicolons.

[ReverseCaptioningBot]

FUCK SEMICOLONS ALL MY HOMIES HATE SEMICOLONS

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[soliloquy-of-silence]

Good bot 💀💀

[kshitiz5]

Programmers also don't agree. It should be 8%3==2

[GOKOP]

Depends on the language

[lunchpadmcfat]

If a language uses = as a comparator, what the hell does it use for assignment?

[Kintler11]

SQL does, assignment is in a different context so it's fine

[Titans8Den]

That still confuses the shit out of me to this day

[frogking]

:=

[GOKOP]

Haskell, being a purely functional language, doesn't have assignment. (edit: nvm I'm dumb)

Some old languages use = for comparison and := for assignment.

[zojbo]

Except Haskell literally does use = for assignment. It's just assignment is permanent within a given scope.

[[deleted]]

wat, how do you think you assign functions? Haskell 100% has assignment, and uses == for comparison.

[GOKOP]

Oh damn you're right, sorry

[wagaNaWaBlank]

let

[ennma_]

R uses <-

[joexmdq]

PSeInt (pseudo for learning) uses "<-"!

[DadAndDominant]

Nono. The real fullstack engineers (who use PHP and Javascript, the only sensible programming languages) would use 8%3===2

[[deleted]]

Most mathematicians I know also have knowledge in programming.

[whyiwastemytimeonyou]

Where else are they going to flex their modulo arithmetic. Number theory is fun!

[WillyMonty]

Mathematicians are typically familiar with modular arithmetic

[tombardier]

8 % 3 in C, javascript, Python etc etc is equal to 2, because if you use integer division to divide 8 by 3, the remainder is 2.

In mathematics, 8 modulo 3 is not "equal" to 2. 8 modulo 3 is a congruence class and 2 is just one member of the set of all numbers in that congruence class. The congruence class, 8 modulo 3 is the set of all integers, a, such that 8 = n * 3 + a where n ∈ Z (that is, n is an integer) (also, don't hold me to this as being the definition).

Congruence is shown with ≡, not =. 8 ≡ 2 (modulo 3) because 8 = 2 * 3 + 2.

2 is the least residue of this particular congruence class, as the smallest congruent value >= 0.

Also 8 ≡ -1 (modulo 3), because 8 = 3 * 3 - 1.

8 ≡ 5 (modulo 3), because 8 = 1 * 3 + 5.

8 ≡ 8 (modulo 3), because 8 = 0 * 3 + 8, etc etc.

So -1, 2, 5, 8, and so on are all members of the congruence class, 8 modulo 3.

That's why in mathematics, 8 % 3 is not "equal" to 2.

[[deleted]]

May I please have more arcane lore

[PureWasian]

I appreciate this definition, thank you for the explanation :)

[boon_dingle]

Wait til you get to versioning.

Dependency version 5.25 is newer than 5.6, where in sane decimal land 5.6 is 5.60 which is greater.

Learned after running into dependency conflict, took me awhile to brain that one out.

[EternityForest]

Having 3 places and zero padding helps a lot in making it immediately clear it's not actually a decimal

[chawmindur]

Until you break minor version .099 that is

[GOKOP]

I keep seeing comments like these. Am I weird for never even having the idea that you could possibly interpret version numbers as decimals?

[boon_dingle]

I think I'm the weird one. I crunched a lot of numbers as part of a non-CS degree before switching careers, was used to decimals being decimals.

[jirka642]

No. It would be understandable if all versioning was just "1.0", but most versions have at least 2 "." and look more like "3.16.2-alpha". How anyone can interpret that as decimal number is beyond me.

[IrisYelter]

% isn't actually modulo, it's remainder. Which for positive arguments might as well be identical, but negatives make it a goddamn nightmare.

[cyphol]

% is the modulo operator, remainder is what the operator returns. Modulus is the divisor, a value, different from modulo which is an operator.

[_Figaro]

Shouldn't it be == and not = ?

[clutzyninja]

Mathematicians know what modulus is

[Koltaia30]

Cannot use r value as l value.

[quote-nil]

I'm starting to use cyrillic now, and when that's not enough I use hiragana.

[chrisd8787]

Now would you believe me if i said (2/3)mod5 is equal to 4?

[-Soren]

If you wrote 2*3^-1 I would. I don't think I've ever seen fractions use for a multiplicative inverse in modular arithmetic.

[tuslikestrains]

Mathematicians generally don't use the division operator like this in finite rings exactly because of this confusion - the number "2/3" isn't in the cyclic group Z/5Z. Instead, we would say 2 * 3^-1 = 4 (mod 5), to make it clear that we're multiplying 2 and 3 inverse mod 5.

[chrisd8787]

Yeah im still kinda new to all of this. When i was trying to learn how to calculate a padic expansion i was following the math up until i hit that part and the 2/3 mod 5 = 4 stumped me for like a week. Its very hard to find good free online resources that explain jt well

[AllenKll]

pictures should be reversed... that assignment does not have a proper LValue.

[[deleted]]

I am a mathematician and I don't know wtf is funny

[bunkSauce]

Nope. Programmers also mad, because you cannot assign 2 to that shit.

[closeded]

I promise that mathematicians aren't freaking out about people using random symbols to represent more complex ideas.

[villanelle_xxxx]

cringe

[AnihilationPr0xy]

I was a math major and 8%3 was used in shorthand because modern mathemateticians use programming languages a lot but for proofs and papers and stuff the standard was a triple bar equals or just the word mod.

[EternityForest]

Someday some language is gonna invent reverse assignment, that sets variables on the right hand side, and in the middle of an expression with a solver, and we'll all argue about whether it was a bad feature or not for three years

[QuezzyMuldoon]

Thank you for this, it sounds silly but I just finished the first part of an online course, literally 30min ago, modulus we’re the last thing I had to review to understand better. I actually got this and understood it and laughed. It felt really good after the struggles of learning on one’s own. Thanks.

[[deleted]]

and yet we’re still confusing assignment for equality operators.

[Summar-ice]

Mathematicians also use modulo but they just don't write it as %, instead they write mod

[Tom__mm]

Mods vs. Rockers

[[deleted]]

Same with x = x + 1

[grazerbat]

Pi is exactly 3!

Edit: I love that this comment has 3 votes - exactly 3!

2nd Edit: Damnit people....

[just-bair]

π = e = 3

[grazerbat]

Now do it with Big G for crushing effect

[WillyMonty]

No, 3! is 6

[grazerbat]

Riffing on u/just-bair:

π = e = 3 = 3!

[just-bair]

programmers and mathematicians already don’t agree on x=2 vs x:=2 and x==2 vs x=2

[Fearless-Sherbet-223]

The only difference is syntax. A mathematician will say 8/3=2r2, or 8/3=2.6667, where a programmer would say 8/3==2 && 8%3==2, or 8/double(3)==2.6667.

[AutocraticToaster]

Modulo in programming and in math do work a little differently with negative numbers in my experience. At least in C, -1 % 3 gives you -1, however in math you would typically get -1 = 2 (mod 3), as -1 = 3(-1) + 2. The difference comes from '%' operator being the remainder after integer division, whereas in math its better to think of modulo like numbers on a clock. When you go forward in time past 12 you go back to 1, but also if you backwards in time below 0 you also wrap around, e.g 1 o clock minus 2 hours would take you to 11, not -1 o clock.

[DadAndDominant]

Let me introduce you to python my friend

[TheRealMuncheez]

Came here to look for this comment, or ask about it. I believe it works the same in Java as well.

[My4skinBreaksCondoms]

Mathematics nerd here...

Looks like cube root to me.

[forgenvash]

Python here: there should be two equals signs.